設計-用java算法實現，栽種四棵樹，保證任意兩棵樹之間距離相等

用java算法實現，栽種四棵樹，保證任意兩棵樹之間距離相等

用java語言實現這個算法，保證任意兩棵樹之間距離相等，現在有想法是設計正四面體，每個點放一課樹，保證任意兩個距離相等

最佳回答：

package com.com.example.demo.Test12_15;

import java.math.BigDecimal;

/**

• com.com.example.demo.Test12_15

• Created by ${SailZhang} on 2016/12/15 0015.
  */
  public class Point {
  Double x ;
  Double y ;
  Double z ;

  public Point() {
  }

  public Point(Double x, Double y, Double z) {
  this.x = x;
  this.y = y;
  this.z = z;
  }

  public Double getX() {
  return x;
  }

  public void setX(Double x) {
  this.x = x;
  }

  public Double getY() {
  return y;
  }

  public void setY(Double y) {
  this.y = y;
  }

  public Double getZ() {
  return z;
  }

  public void setZ(Double z) {
  this.z = z;
  }

  @Override
  public String toString() {
  return "Point{" +
  "x=" + x +
  ", y=" + y +
  ", z=" + z +
  '}';
  }
  }

 package com.com.example.demo.Test12_15;

import java.math.BigDecimal;
import java.math.MathContext;

/**
 * com.com.example.demo.Test12_15
 * Created by ${SailZhang} on 2016/12/15 0015.
 */
public class Test {
    public static void main(String[] args) {
        Point p1 = new Point(0.0,0.0,0.0);
        Point p2 = new Point(1.0,1.0,1.0);
        for (double i = -2.0;i<=2;i += 0.1){
            for (double j = -2.0;j<=2;j += 0.1){
                for (double k = -2.0;k<=2;k += 0.1){
                    Point p3 = new Point(i,j,k);
                    if (sub(getLengthPow(p1,p2),getLengthPow(p1,p3)) == 0
                            && sub(getLengthPow(p1,p2),getLengthPow(p2,p3)) == 0){
                        System.out.println(p3.toString());
                    }
                }
            }
        }
    }
    public static Double getLengthPow(Point p1, Point p2){
        double xx = p1.getX() - p2.getX();
        double yy = p1.getY() - p2.getY();
        double zz = p1.getZ() - p2.getZ();
        return Math.pow(xx,2)+ Math.pow(yy,2)+Math.pow(zz,2);
    }
    public static double sub(double v1,double v2){
        BigDecimal b1 = new BigDecimal(Double.toString(v1));
        BigDecimal b2 = new BigDecimal(Double.toString(v2));
        return b1.subtract(b2).setScale(0,BigDecimal.ROUND_HALF_UP).doubleValue();
    }
}

這個必然存在小數的. 我給自己坑了