如題,自己在系統中直接上傳的話是可以的,但用代碼上傳就不行了,代碼是這樣的
package cn.com.sensetech.ftp;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import org.apache.commons.net.ftp.FTPClient;
import org.apache.commons.net.ftp.FTPReply;
public class Upload
{
/**
@return 成功返回true,否則返回false
*/
public static boolean uploadFile(String url,int port,String username, String password, String path, String filename, InputStream input) {
boolean success = false;
FTPClient ftp = new FTPClient();
try
{
int reply;
ftp.connect(url, port);//連接FTP服務器
//如果采用默認端口,可以使用ftp.connect(url)的方式直接連接FTP服務器
ftp.login(username, password);//登錄
reply = ftp.getReplyCode();
if (!FTPReply.isPositiveCompletion(reply))
{
ftp.disconnect();
return success;
}
ftp.changeWorkingDirectory(path);
ftp.storeFile(filename, input);
input.close();
ftp.logout();
success = true;
}
catch (IOException e)
{
e.printStackTrace();
}
finally
{
if (ftp.isConnected())
{
try
{
ftp.disconnect();
}
catch (Exception e)
{
e.printStackTrace();
}
}
}
return success;
}
public static void main(String[] args)
{
try
{
String filepath = "D:/upload/liuqian.txt";
FileInputStream in = new FileInputStream(new File(filepath));
boolean flag = uploadFile("localhost", 21, "lq", "123", "D:/upload", "walmartDemo", in);
System.out.println(flag);
}
catch (Exception e)
{
e.printStackTrace();
}
}
}
提示出錯信息
org.apache.commons.net.ftp.FTPConnectionClosedException: Connection closed without indication.
at org.apache.commons.net.ftp.FTP.__getReply(FTP.java:317)
at org.apache.commons.net.ftp.FTP.__getReply(FTP.java:294)
at org.apache.commons.net.ftp.FTP._connectAction_(FTP.java:400)
at org.apache.commons.net.ftp.FTPClient._connectAction_(FTPClient.java:924)
at org.apache.commons.net.SocketClient.connect(SocketClient.java:183)
at org.apache.commons.net.SocketClient.connect(SocketClient.java:203)
at cn.com.sensetech.ftp.Upload.uploadFile(Upload.java:30)
at cn.com.sensetech.ftp.Upload.main(Upload.java:105)
false
調試的時候發現錯誤出現在這裡
finally
{
if (ftp.isConnected())
{
try
{
ftp.disconnect();
}
catch (Exception e)
{
e.printStackTrace();
}
}
這究竟是怎麼回事啊,怎麼修改才能夠跑通,本人新手,求各位大師幫忙,感激不盡
http://aspnetdb.iteye.com/blog/970408