c++基礎-求解C++繼承類構造函數的簡單問題(類內聲明,類外定義)

求解C++繼承類構造函數的簡單問題(類內聲明,類外定義)

class person
{
public:
person(int num1, string name1);
..
private:
int num;
string name;
};
person::person(int num1, string name1)
{
num = num1;
name = name1;
}

class student :public person
{
public:
student(int num1, string name1, int cnum1, float score1) :person(num1, name1);
...
private:
int cnum;
float score;
};

student::student(int num1, string name1, int cnum1, float score1) :person(num1, name1)
{
cnum = cnum1;
score = score1;
}

繼承類的構造函數,在類內定義,類外聲明,這種方式為什麼不可以編譯?

最佳回答：

聲明的時候不能調用基類的構造函數，定義的時候才可以，因此，建議改為：
class person
{
public:
person(int num1, string name1);
..
private:
int num;
string name;
};
person::person(int num1, string name1)
{
num = num1;
name = name1;
}
class student :public person
{
public:
student(int num1, string name1, int cnum1, float score1) ;
...
private:
int cnum;
float score;
};
student::student(int num1, string name1, int cnum1, float score1) :person(num1, name1)
{
cnum = cnum1;
score = score1;
}