xml-asp.net 如何讀取 這樣的XML 取得它的loginname和realname

asp.net 如何讀取 這樣的XML 取得它的loginname和realname

 <cas:serviceResponse xmlns:cas='http://www.yale.edu/tp/cas'>
<cas:authenticationSuccess>
        <cas:user>bb</cas:user>
        <cas:attributes  nid='1'>
        <cas:id>2</cas:id>
        <cas:loginname>bb</cas:loginname>
        <cas:role>2</cas:role>
        <cas:realname>bbggg</cas:realname>
        </cas:attributes>
    </cas:authenticationSuccess>
</cas:serviceResponse>

最佳回答：

```void Main()
{
string xml = @"

cas:authenticationSuccess

cas:userbb/cas:user



cas:id2/cas:id

cas:loginnamebb/cas:loginname

cas:role2/cas:role

cas:realnamebbggg/cas:realname

/cas:attributes

/cas:authenticationSuccess

/cas:serviceResponse";

XDocument xmlPage = XDocument.Parse(xml);

XNamespace ns = "http://www.xxx.edu/tp/cas";

       var query = from x in xmlPage.Descendants(ns+"authenticationSuccess")    
                   from y in x.Element(ns+"attributes").Elements()
                   select y;
       foreach(XElement item in query) 
            Console.WriteLine("{0}:\t  {1}",item.Name.LocalName,item.Value);

     /*
     id:      2
    loginname:    bb
    role:     2
    realname:     bbggg
     */

}