parse-sax 解析：從 div 標簽中獲取值

sax 解析：從 div 標簽中獲取值

在 android 應用程序中，我要解析一個 xml 頁面。xml 頁面中的數據是下面這種格式：

<root>
<tag1>data</tag1>

<tag2> 
<div>data1</div><div>data2</div>
</tag2>
</root>

通過 sax 解析來獲取數據：

if (localName.equalsIgnoreCase("tag1"))
if (localName.equalsIgnoreCase("tag2"))

但是我不能從tag2中得到任何數據，能從tag1中獲得值。我想獲取所有數據包括div標簽
然後把數據顯示在html頁面上。

最佳回答：

使用下面的代碼，應該能達到你要的功能。

currentTag = localName;
        if ("tag1".equalsIgnoreCase(localName)) {
            responseTag = new StringBuffer();
        }else if ("tag2".equalsIgnoreCase(localName)) {
            responseTag = new StringBuffer();
        }else if ("div".equalsIgnoreCase(localName)) {
            responseTag = new StringBuffer();
        }
    }

    @Override
    public void endElement(String uri, String localName, String name)
            throws SAXException {
        super.endElement(uri, localName, name);
        String responseValue = responseTag.toString().trim();

        if ("tag1".equalsIgnoreCase(localName)) {
            Log.v("TAG", "Tag 1 value "+responseValue);
        }else if ("tag2".equalsIgnoreCase(localName)) {
            Log.v("TAG", "Tag 2 value "+responseValue);
        }else if ("div".equalsIgnoreCase(localName)) {
            Log.v("TAG", "div value "+responseValue);
        }
    }

    @Override
    public void characters(char[] ch, int start, int length)
            throws SAXException {
        super.characters(ch, start, length);
        str = new String(ch, start, length);

        if ("tag1".equalsIgnoreCase(currentTag)) {
            responseTag.append(str);
        }else if ("tag2".equalsIgnoreCase(currentTag)) {
            responseTag.append(str);
        }else if ("div".equalsIgnoreCase(currentTag)) {
            responseTag.append(str);
        }
    }
}