objective c-UILable鏈接打開safari浏覽器

UILable鏈接打開safari浏覽器

有自定義UITableViewCell 其中包含兩枚UILabel。表格單元顯示information/text。一些單元設置：

cell.myTextlabel.text = @"http://www.google.de"

我想在點擊這些text鏈接時，safari浏覽器可以打開網頁。應該怎麼實現？

最佳回答：

設置userInteractionEnabled 為 YES 。添加一個姿勢識別器：

myLabel.userInteractionEnabled = YES;
UITapGestureRecognizer *gestureRec = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(openUrl:)];
gestureRec.numberOfTouchesRequired = 1;
gestureRec.numberOfTapsRequired = 1;
[myLabel addGestureRecognizer:gestureRec];
[gestureRec release];

然後實習操作方法：

- (void)openUrl:(id)sender
{
    UIGestureRecognizer *rec = (UIGestureRecognizer *)sender;

    id hitLabel = [self.view hitTest:[rec locationInView:self.view] withEvent:UIEventTypeTouches];

    if ([hitLabel isKindOfClass:[UILabel class]]) {
        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:((UILabel *)hitLabel).text]];
    }
}