就是調用記錄集A,調用條件記錄集A中有1列是等於記錄集B的一列
$query_RecordsetA= "SELECT * FROM member WHERE username like ' $row_RecordsetB['author'] '";我這樣寫報錯了
注意+那裡試字符串連接符,看看你什麼語言,做對應調整
"SELECT * FROM member WHERE username like '" + $row_RecordsetB['author'] + "' "