Commonly used regression model evaluation indicatorspython計算邏輯.python和相關package版本:
import sys
import sklearn
import pandas as pd
import numpy as np
import math
print( "Python版本:", sys. version)
print( "sklearn版本:", sklearn. __version__)
print( "pandas:", pd. __version__)
print( "numpy:", np. __version__)
Python版本: 3.7.0 (default, Jun 28 2018, 08:04:48) [MSC v.1912 64 bit (AMD64)]
sklearn版本: 0.22
pandas: 0.23.4
numpy: 1.17.4
from sklearn. metrics import mean_absolute_error
y_true = [ 3, - 0.5, 2, 7]
y_pred = [ 2.5, 0.0, 2, 8]
mean_absolute_error( y_true, y_pred)
0.5
sum([ abs( y_true[ i] - y_pred[ i]) for i in range( len( y_true))]) / len( y_true)
0.5
from sklearn. metrics import mean_squared_error
y_true = [ 3, - 0.5, 2, 7]
y_pred = [ 2.5, 0.0, 2, 8]
mean_squared_error( y_true, y_pred)
0.375
sum([ abs( y_true[ i] - y_pred[ i]) * * 2 for i in range( len( y_true))]) / len( y_true)
0.375
這個沒啥說的,mseJust open
math. sqrt( mean_squared_error( y_true, y_pred))
0.6123724356957945
from sklearn. metrics import r2_score
r2_score( y_true, y_pred)
0.9486081370449679
1 - sum([( y_true[ i] - y_pred[ i]) * * 2 for i in range( len( y_true))]) / sum(
[( y_true[ i] - sum( y_true) / len( y_true)) * * 2 for i in range( len( y_true))])
0.9486081370449679
mapeSince there may be a denominator of 0的情況,So there are no statistics for now.Combine other metrics,格式化輸出:
from sklearn. metrics import mean_absolute_error
from sklearn. metrics import mean_squared_error
from sklearn. metrics import r2_score
def reg_metric( y_true, y_predict):
mae = mean_absolute_error( y_true, y_pred)
mse = mean_squared_error( y_true, y_pred)
rmse = math. sqrt( mean_squared_error( y_true, y_pred))
r2 = r2_score( y_true, y_pred)
print( "MAE:", mae)
print( "MSE:", mse)
print( "RMSE:", rmse)
print( "R Square:", r2)
reg_metric( y_true = y_true, y_predict = y_pred)
MAE: 0.5
MSE: 0.375
RMSE: 0.6123724356957945
R Square: 0.9486081370449679
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