活動地址：CSDN21天學習挑戰賽
學習的最大理由是想擺脫平庸,早一天就多一份人生的精彩;遲一天就多一天平庸的困擾.各位小伙伴,如果您：
想系統/深入學習某技術知識點…
一個人摸索學習很難堅持,想組團高效學習…
想寫博客但無從下手,急需寫作干貨注入能量…
熱愛寫作,願意讓自己成為更好的人…
…
歡迎參與CSDN學習挑戰賽,成為更好的自己,請參考活動中各位優質專欄博主的免費高質量專欄資源（這部分優質資源是活動限時免費開放喔~）,按照自身的學習領域和學習進度學習並記錄自己的學習過程.您可以從以下3個方面任選其一著手（不強制）,或者按照自己的理解發布專欄學習作品,參考如下：
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1,學習目標
提示：可以添加學習目標
例如： 一周掌握 Python 入門知識
2,學習內容
提示：可以添加要學的內容
例如：
A,掌握 Python 基本語法
B,掌握 Python 列表、字典、元組等集合類型的用法
C,掌握 Python 函數
D,掌握 Python 常用模塊
E, 掌握 Python 模塊與包
F,掌握 Python 類與對象
3,學習時間
每天拿出來兩個小時
4,學習產出
CSDN技術博客 每天一篇
name1 = "Zhang Xinxiao"
name2 = "潘磊"
# 列表的構建 語法格式 [數據對象,...,]
# 特點1： 列表中的元素可以是任意數據類型
# 特點2： 列表中的元素個數沒有限制
l1 = [100, "hello", True]
print(type(l1)) # list
l2 = [100, 2, 34, 5]
print(len(l2)) # 4
names = ["", "", "", ]
l = [10, 20, 30, 40, 50]
# A list is a sequence type
# 一 支持正負索引 數據對象[索引]
# print(l[1])
# print(l[-3])
print(id(l))
l[0] = 100
print(l)
print(id(l))
# 二 支持切片: 數據對象[開始索引:結束索引:步長] 顧頭不顧尾
# print(l[1:4]) # [20, 30, 40]
# print(l[-4:-1]) # [20, 30, 40]
# print(l[1:]) # [20, 30, 40, 50]
# print(l[:3]) # [20, 30, 40, 50]
# print(l[:]) # [10, 20, 30, 40, 50]
# print(l[-2:-5:-1]) # [40, 30, 20]
# 三 in操作: Whether a value is an element value in a list
# names = ["rain", "yuan", "alvin"]
# print("rai" in names)
# print("rai" in "rain")
# print(1 in ["1", 2, 3])
# # 案例
# n = 0
# while n < 100:
#
# # if n != 88 and n != 66:
# # print(n)
#
# if n not in [66, 88, 33, 44, 55]:
# print(n)
#
# n += 1
# 拼接 +
l1 = [1, 2, 3]
l2 = [4, 5, 6]
print(l1 + l2) # [1, 2, 3, 4, 5, 6]
print(l1)
print(l2)
# 列表內置方法： 列表對象.方法()
# Lists have built-in methods for managing the data in the list：增刪改查
# 一 增：append:追加 insert:Insert a value anywhere extend
# print("hello".upper())
# 案例1： append
# l = [10, 20, 30, 40]
# ret = l.append(50)
# print(l) # [10, 20, 30, 40,50]
# print(ret) # None
# 案例2: insert(索引,值)
# l = [10, 20, 30, 40]
# l.insert(0, 100)
# print(l) # [100, 10, 20, 30, 40]
# 案例3: extend
# l1 = [10, 20, 30, [4, 5, 6]]
# 如何獲取5的值
# print(l1[3][1])
# print(len(l1))
# l2 = [1, 2, 3]
# l3 = [4, 5, 6]
# l2.append(l3)
# print(l2) # [1,2,3,[4,5,6]]
# print(len(l2))
# print(id(l2))
# ret = l2.extend(l3)
# print("ret:", ret)
# print(l2) # [1, 2, 3, 4, 5, 6]
# print(id(l2))
# 二 刪 pop():按索引刪除 remove()：按值刪除 clear()：清空
# names = ["張三", "李四", "王五"]
# 按索引刪除
# del_name = names.pop(0) # pop返回刪除元素值
# print(names)
# print("將%s刪除掉了" % del_name)
# 按元素值刪除
# ret = names.remove("李四")
# print(ret) # None
# print(names)
# 清空列表
# names.clear()
# print(names) # []
# del names
# print(names)
# 三 改: There is no built-in method to modify an element,It can only be done by indexing
# l = [1, 2, 3]
# l[0] = 100
# print(l) # [100, 2, 3]
# 四 查 index count sort reverse
# names = ["張三", "李四", "王五", "李四"]
# print(names.index("李四"))
# print(names.count("李四"))
#
# age_list = [20, 22, 18, 45, 32]
# # age_list.reverse() # age_list :[32,45,18,22,20]
#
# age_list.sort(reverse=True)
# print(age_list) # [45, 32, 22, 20, 18]
#
# age_list = ["100", "10", "12"]
# age_list.sort()
# print(age_list) # ['10', '100', '32']
# 練習題
# 將字符串 "20,15,34,188,26"All numbers in are sorted by largest to smallest"-"as a delimiter to form a new string
# 方案1：
# s = "20,15,34,188,26"
# l1 = s.split(",")
# print(l1) # ['20', '15', '34', '188', '26']
# l2 = []
# for i in l1:
# l2.append(int(i))
#
# print(l2)
# l2.sort(reverse=True)
# print(l2)
# l3 = []
# for i in l2: # l2: [15, 20, 26, 34, 188]
# l3.append(str(i))
# print(l3) # ['15', '20', '26', '34', '188']
#
# print("-".join(l3)) # 15-20-26-34-188
# 方案2
s = "20,15,34,188,26"
l1 = s.split(",") # ['20', '15', '34', '188', '26']
l2 = [int(i) for i in l1]
l2.sort(reverse=True)
l3 = [str(i) for i in l2]
print("-".join(l3)) # 188-34-26-20-15
# 列表內置方法： 列表對象.方法()
# Lists have built-in methods for managing the data in the list：增刪改查
# 一 增：append:追加 insert:Insert a value anywhere extend
# print("hello".upper())
# 案例1： append
# l = [10, 20, 30, 40]
# ret = l.append(50)
# print(l) # [10, 20, 30, 40,50]
# print(ret) # None
# 案例2: insert(索引,值)
# l = [10, 20, 30, 40]
# l.insert(0, 100)
# print(l) # [100, 10, 20, 30, 40]
# 案例3: extend
# l1 = [10, 20, 30, [4, 5, 6]]
# 如何獲取5的值
# print(l1[3][1])
# print(len(l1))
# l2 = [1, 2, 3]
# l3 = [4, 5, 6]
# l2.append(l3)
# print(l2) # [1,2,3,[4,5,6]]
# print(len(l2))
# print(id(l2))
# ret = l2.extend(l3)
# print("ret:", ret)
# print(l2) # [1, 2, 3, 4, 5, 6]
# print(id(l2))
# 二 刪 pop():按索引刪除 remove()：按值刪除 clear()：清空
# names = ["張三", "李四", "王五"]
# 按索引刪除
# del_name = names.pop(0) # pop返回刪除元素值
# print(names)
# print("將%s刪除掉了" % del_name)
# 按元素值刪除
# ret = names.remove("李四")
# print(ret) # None
# print(names)
# 清空列表
# names.clear()
# print(names) # []
# del names
# print(names)
# 三 改: There is no built-in method to modify an element,It can only be done by indexing
# l = [1, 2, 3]
# l[0] = 100
# print(l) # [100, 2, 3]
# 四 查 index count sort reverse
# names = ["張三", "李四", "王五", "李四"]
# print(names.index("李四"))
# print(names.count("李四"))
#
# age_list = [20, 22, 18, 45, 32]
# # age_list.reverse() # age_list :[32,45,18,22,20]
#
# age_list.sort(reverse=True)
# print(age_list) # [45, 32, 22, 20, 18]
#
# age_list = ["100", "10", "12"]
# age_list.sort()
# print(age_list) # ['10', '100', '32']
# 練習題
# 將字符串 "20,15,34,188,26"All numbers in are sorted by largest to smallest"-"as a delimiter to form a new string
# 方案1：
# s = "20,15,34,188,26"
# l1 = s.split(",")
# print(l1) # ['20', '15', '34', '188', '26']
# l2 = []
# for i in l1:
# l2.append(int(i))
#
# print(l2)
# l2.sort(reverse=True)
# print(l2)
# l3 = []
# for i in l2: # l2: [15, 20, 26, 34, 188]
# l3.append(str(i))
# print(l3) # ['15', '20', '26', '34', '188']
#
# print("-".join(l3)) # 15-20-26-34-188
# 方案2
s = "20,15,34,188,26"
l1 = s.split(",") # ['20', '15', '34', '188', '26']
l2 = [int(i) for i in l1]
l2.sort(reverse=True)
l3 = [str(i) for i in l2]
print("-".join(l3)) # 188-34-26-20-15
# l = [1, 2, 3, 4, 5]
# l2 = []
# for i in l:
# l2.append(i * i)
# print(l2)
# 列表推導式：[表達式 for i in 可迭代對象]
l = [1, 2, 3, 4, 5]
l2 = [i * i for i in l]
print(l2) # [1,4,9,16,25]
# 字典是python的唯一一個hash映射的數據類型
l = ["rain", 22, "male"]
# A key-value pair in a dictionary is an element
# 字典的鍵必須是不可變數據類型（Except list and dictionary data types）,Commonly used are strings and integers
# 字典的值可以是任意數據類型
# In principle, there are no restrictions on the key-value pairs of a dictionary
# 字典特點：無序,鍵不能重復
d = {
"name": "rain", "age": 22, "gender": "male"}
print(d, type(d)) # dict
stu = {
"name": "yuan", "age": 22}
# print(len(stu))
# 一 通過鍵查詢值 列表對象[索引] 字典對象[鍵]
print(stu["name"]) # yuan
print(stu["age"]) # yuan
print(stu["xxx"]) # 鍵不存在報錯
# 二 添加或修改
stu["gender"] = "male" # 鍵不存在,It is to add key-value pairs
stu["age"] = 24 # 鍵存在,Then modify the key-value pair
print(stu)
# 刪除鍵值對 del命令
del stu["gender"]
print(stu)
# 字典的內置方法：Data management for dictionary objects
stu = {
"name": "yuan", "age": 22, "gender": "female"}
# 一 查看鍵值對
# print(stu.get("name"))
# print(stu.get("age"))
# print(stu.get("gender", "male"))
# print(stu.keys()) # ['name', 'age']
# print(stu.values()) # ['yuan', 22]
# print(stu.items()) # [('name', 'yuan'), ('age', 22)]
# 二 添加或修改鍵值對：update
# stu.update({"age":32,"gender":"male"})
# ret = stu.setdefault("gender", "male") # 獲取name鍵的值
# print(ret)
# print(stu)
# 三 刪除鍵值對：pop
# ret = stu.pop("age")
# stu.popitem()
# print("age",ret)
# print("stu",stu)
stu = {
"name": "yuan", "age": 22, "gender": "female"}
# print(stu.get("name"))
# k = "age"
# print(stu.get(k))
# 方式1
# for i in stu:
# print(i, stu.get(i)) # 遍歷字典的鍵
# 方式2
# x = [1, 2, 3]
# print(x, type(x)) # tuple
# a, *b = [1, 2, 3]
# print(a, b)
for k,v in stu.items(): # [("name","yuan")],("age",22),("gender","male)]
print(k,v)
# Tuples are called read-only lists
l = [1, 2, 3]
l[0] = 100
t = (1, 2, 3)
print(t, type(t)) # tuple
print(t[1])
print(t[1:])
print(1 in t)
t.count(1)
t.index(1)
for i in t:
print(i)
# 練習1
stu = {
"name": "yuan", "score": [100, 90, 80]}
# Get foreign language grades
l = stu.get("score") # [100, 90, 80]
print(l[-1])
print(stu.get("score")[-1])
# 練習2
stu = {
"name": "yuan", "score": {
"chinese": 100, "math": 90, "english": 80}}
print(len(stu))
print(stu.get("score").get("english"))
# 練習3
data = [
{
"sid":1001,"name": "rain", "age": 22},
{
"sid":1003,"name": "eric", "age": 32},
{
"sid":1002,"name": "alvin", "age": 24},
]
for stu_dict in data:
name = stu_dict.get("name")
age = stu_dict.get("age")
print("姓名：%s,年齡：%d" % (name, age))
data2 = {
1001: {
"name": "rain", "age": 22},
1002: {
"name": "eric", "age": 32},
1003: {
"name": "alvin", "age": 24},
}
print(data2.get(1001).get("name"))
for stu_id,stu_info in data2.items():
name = stu_info.get("name")
age = stu_info.get("age")
print("學號：%s,姓名：%s,年齡：%d" % (stu_id,name, age))
# 案例1
# l1 = [1, 2, 3]
# l2 = [4, 5, l1]
# print(l2) # [4, 5, [1, 2, 3]]
# l1[0] = 100
# print(l2)
# 案例2
stu01 = {
"name": "rain"}
stus_dict = {
1001: stu01}
print(stus_dict)
stu01["name"] = "alvin"
print(stus_dict)
print(id(stus_dict[1001]))
stus_dict[1001] = {
"name": "eric"}
print(id(stus_dict[1001]))
print(id(stu01))
# Determine what data type and format the data is stored in
students_dict = {
1001: {
"name": "yuan",
"scores": {
"chinese": 100,
"math": 89,
"english": 100,
}
},
1002: {
"name": "rain",
"scores": {
"chinese": 100,
"math": 100,
"english": 100,
}
},
}
while 1:
print(''' 1. 查看所有學生成績 2. Add a student grade 3. 修改一個學生成績 4. Delete a student grade 5. 退出程序 ''')
choice = input("請輸入您的選擇：")
if choice == "1":
# 查看所有學生信息
print("*" * 60)
for sid, stu_dic in students_dict.items():
# print(sid,stu_dic)
name = stu_dic.get("name")
chinese = stu_dic.get("scores").get("chinese")
math = stu_dic.get("scores").get("math")
english = stu_dic.get("scores").get("english")
print("學號:%4s 姓名:%4s 語文成績：%4s 數學成績%4s 英文成績:%4s" % (sid, name, chinese, math, english))
print("*" * 60)
elif choice == "2":
while 1:
sid = input("請輸入學生學號>>>")
# Determine whether the student number exists
if int(sid) in students_dict: # 該學號已經存在！
print("該學號已經存在！")
else: # # 該學號不存在！
break
name = input("請輸入學生姓名>>>")
chinese_score = input("請輸入學生語文成績>>>")
math_score = input("請輸入學生數學成績>>>")
english_score = input("請輸入學生英語成績>>>")
# Build a student dictionary
scores_dict = {
"chinese": chinese_score,
"math": math_score,
"english": english_score,
}
stu_dic = {
"name": name,
"scores": scores_dict
}
print("stu_dic", stu_dic)
students_dict[int(sid)] = stu_dic
elif choice == "3":
while 1:
sid = input("請輸入學生學號>>>")
# Determine whether the student number exists
if int(sid) in students_dict: # 該學號已經存在！
break
else: # # 該學號不存在！
print("The modified student ID does not exist！")
chinese_score = input("請輸入學生語文成績>>>")
math_score = input("請輸入學生數學成績>>>")
english_score = input("請輸入學生英語成績>>>")
# 修改學生成績
scores_dict = {
"chinese": chinese_score,
"math": math_score,
"english": english_score,
}
students_dict.get(int(sid)).update({
"scores": scores_dict})
print("修改成功")
elif choice == "4":
while 1:
sid = input("請輸入學生學號>>>")
# Determine whether the student number exists
if int(sid) in students_dict: # 該學號已經存在！
break
else: # # 該學號不存在！
print("The modified student ID does not exist！")
students_dict.pop(int(sid))
print("刪除成功")
elif choice == "5":
# 退出程序
break
else:
print("輸入有誤！")
