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Given the header of a sorted linked list head
, Delete all duplicate elements , Make each element appear only once . return Sorted linked list .
Example 1:
Input :head = [1,1,2]
Output :[1,2]
Example 2:
Input :head = [1,1,2,3,3]
Output :[1,2,3]
Tips :
[0, 300]
Inside -100 <= Node.val <= 100
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def deleteDuplicates(self, head: ListNode) -> ListNode:
tmp_head = ListNode(-1,head)
l,r = tmp_head,tmp_head.next
while r:
while r.next and r.val == r.next.val:
r = r.next
l.next = r
l = l.next
r = r.next
l.next = None
return tmp_head.next