程序師世界是廣大編程愛好者互助、分享、學習的平台,程序師世界有你更精彩!
首頁
編程語言
C語言|JAVA編程
Python編程
網頁編程
ASP編程|PHP編程
JSP編程
數據庫知識
MYSQL數據庫|SqlServer數據庫
Oracle數據庫|DB2數據庫
您现在的位置: 程式師世界 >> 編程語言 >  >> 更多編程語言 >> Python

Python description leetcode 515 Find the maximum value in each tree row

編輯:Python

Python describe LeetCode 515. Find the maximum in each tree row

Hello everyone , I'm Qi Guanjie (qí guān jié ), stay 【 Qi Guanjie 】 official account 、CSDN、GitHub、B Share some technical blog posts on the website and other platforms , It mainly includes front-end development 、python The backend development 、 Applet development 、 Data structure and algorithm 、docker、Linux Common operation and maintenance 、NLP And other related technical blog , Time flies , Future period , come on. ~

If you love bloggers, you can focus on the bloggers' official account. 【 Qi Guanjie 】(qí guān jié), The articles inside are more complete and updated faster . If you need to find a blogger, you can leave a message at the official account. , I will reply to the message as soon as possible .


This article was originally written as 【 Qi Guanjie 】(qí guān jié ), Please support the original , Some platforms have been stealing blog articles maliciously !!! All articles please pay attention to WeChat official account 【 Qi Guanjie 】.

subject

Given the root node of a binary tree root , Please find the maximum value of each layer in the binary tree .

Example 1:

 Input : root = [1,3,2,5,3,null,9]
Output : [1,3,9]

Example 2:

 Input : root = [1,2,3]
Output : [1,3]

Tips :

  • The range of the number of nodes in a binary tree is [0,104]
  • -231 <= Node.val <= 231 - 1

Python describe

Level traversal

# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def largestValues(self, root: Optional[TreeNode]) -> List[int]:
if not root:
return []
res = []
q = [root]
while q:
tmp_max,n = q[0].val,len(q)
for i in range(n):
node = q[0]
tmp_max = max(node.val,tmp_max)
q.remove(q[0])
if node.left:
q.append(node.left)
if node.right:
q.append(node.right)
res.append(tmp_max)
return res

  1. 上一篇文章:
  2. 下一篇文章:
Copyright © 程式師世界 All Rights Reserved