data

The data style is as follows , Nested dictionary for list

example = [
{
'id':1,'name':'b'},
{
'id':2,'name':'a'}
]

Although the basic principles have been understood , Still want to be wordy , In computer language , There is such a logical relationship

>>> 2 > 1
True

>>> 'a' < 'b'
True

sorted+lambda

Can solve your worries

• Use key Parameter determines the sort field
  - So pass in the list elements , That is, the field , Let's go back to the dictionary [key], That's the value
• Use reverse Parameters determine ascending and descending order

1. according to id Ascending

>>> sorted(example,key=lambda x:x['id'],reverse=False)
[{
'id': 1, 'name': 'b'}, {
'id': 2, 'name': 'a'}]

2. according to id Descending

>>> sorted(example,key=lambda x:x['id'],reverse=True)
[{
'id': 2, 'name': 'a'}, {
'id': 1, 'name': 'b'}]

3. according to name Ascending

>>> sorted(example,key=lambda x:x['name'],reverse=False)
[{
'id': 2, 'name': 'a'}, {
'id': 1, 'name': 'b'}]

4. according to name Descending

>>> sorted(example,key=lambda x:x['name'],reverse=True]
[{
'id': 1, 'name': 'b'}, {
'id': 2, 'name': 'a'}]

Tips

• sorted Will not change the original array , So you need to assign values to new variables
  After the operation just now , The original example The variable output is followed by

>>> example
[{
'id': 1, 'name': 'b'}, {
'id': 2, 'name': 'a'}]

There was no change

• lambda Functions are easy to confuse for beginners , You can take shorthand like this

lambda Pass in the parameter : Output results

Equivalent to

def Isn't there a name ( Pass in the parameter ):
return Output results