Python time operation

Get the current time

import datetime
import time
i = datetime.datetime.now()
print (" The current date and time is %s" % i)
print (" The current year is %s" %i.year)
print (" The current month is %s" %i.month)
print (" The current date is %s" %i.day)
print (" The current hour is %s" %i.hour)
print (" The current minute is %s" %i.minute)
print (" The current second is %s" %i.second)

Compare the time

i = str(datetime.datetime.now())
print(i[:10]) ###2022-06-17
s1=i[:10]
s2='2022-06-26'
s1_1 = time.strptime(s1, '%Y-%m-%d')
s2_2 = time.strptime(s2, '%Y-%m-%d')
print(s1_1>s2_2) ###False

Turn a time string into a timestamp

import time
s2='2022-06-23'
### Convert to time tuple first
s2_2 = time.strptime(s2, '%Y-%m-%d')
### And then turn to timestamp
res=int(time.mktime(s1_1))

## One more day
res=(datetime.datetime.now()+datetime.timedelta(days=1)).strftime("%Y-%m-%d %H:%M:%S")
print(res)
## One more hour
res=(datetime.datetime.now()+datetime.timedelta(hours=1)).strftime("%Y-%m-%d %H:%M:%S")
print(res)
## One more minute
res=(datetime.datetime.now()+datetime.timedelta(minutes=1)).strftime("%Y-%m-%d %H:%M:%S")
print(res)