Explain the usage of the join() function in Python

function ：string.join()

Python There is join() and os.path.join() Two functions , The specific functions are as follows ：
    join()：    Connection string array . The string 、 Tuples 、 Elements in the list with the specified characters ( Separator ) The connection generates a new string
    os.path.join()：  Combine multiple paths and return

One 、 Function description
1、join() function

grammar ：  'sep'.join(seq)

Parameter description
sep： Separator . Can be null
seq： The sequence of elements to connect 、 character string 、 Tuples 、 Dictionaries
The above grammar is ： With sep As a separator , take seq All the elements are combined into a new string

Return value ： Returns a separator sep String generated after connecting elements

2、os.path.join() function

grammar ：  os.path.join(path1[,path2[,......]])

Return value ： Combine multiple paths and return

notes ： Parameters before the first absolute path will be ignored

Two 、 example

# Operate on the sequence （ Separate use ' ' And ':' As a separator ）
>>> seq1 = ['hello','good','boy','doiido']
>>> print ' '.join(seq1)
hello good boy doiido
>>> print ':'.join(seq1)
hello:good:boy:doiido
# Operate on strings
>>> seq2 = "hello good boy doiido"
>>> print ':'.join(seq2)
h:e:l:l:o: :g:o:o:d: :b:o:y: :d:o:i:i:d:o
# Operate on tuples
>>> seq3 = ('hello','good','boy','doiido')
>>> print ':'.join(seq3)
hello:good:boy:doiido
# Operate the dictionary
>>> seq4 = {'hello':1,'good':2,'boy':3,'doiido':4}
>>> print ':'.join(seq4)
boy:good:doiido:hello
# Merge catalog
>>> import os
>>> os.path.join('/hello/','good/boy/','doiido')
'/hello/good/boy/doiido'

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