Hello everyone , I'm Qi Guanjie (qí guān jié ), stay 【 Qi Guanjie 】 official account 、CSDN、GitHub、B Share some technical blog posts on the website and other platforms , It mainly includes front-end development 、python The backend development 、 Applet development 、 Data structure and algorithm 、docker、Linux Common operation and maintenance 、NLP And other related technical blog , Time flies , Future period , come on. ~
If you love bloggers, you can focus on the bloggers' official account. 【 Qi Guanjie 】(qí guān jié), The articles inside are more complete and updated faster . If you need to find a blogger, you can leave a message at the official account. , I will reply to the message as soon as possible .
This article was originally written as 【 Qi Guanjie 】(qí guān jié ), Please support the original , Some platforms have been stealing blog articles maliciously !!! All articles please pay attention to WeChat official account 【 Qi Guanjie 】.
Give you a fixed length array of integers arr
, Please copy every zero that appears in the array , And shift the rest of the elements to the right .
Be careful : Please do not write elements beyond the length of the array .
requirement : Please input the array In situ Make the above modifications , Don't return anything from a function .
Example 1:
Input :[1,0,2,3,0,4,5,0]
Output :null
explain : After calling the function , The input array will be modified to :[1,0,0,2,3,0,0,4]
Example 2:
Input :[1,2,3]
Output :null
explain : After calling the function , The input array will be modified to :[1,2,3]
Tips :
1 <= arr.length <= 10000
0 <= arr[i] <= 9
class Solution:
def duplicateZeros(self, arr: List[int]) -> None:
""" Do not return anything, modify arr in-place instead. """
n = len(arr)
i = 0
while i < n:
if arr[i] == 0:
j = n -1
while i < j:
arr[j] = arr[j-1]
j -= 1
i += 1
i += 1
Project IntroductionOnline clo
A library commonly used by cra