Acwing game time c++ Python

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Problem description ：

according to y The general idea , Calculate by converting to minutes , Avoid complex multiple judgment statements .

First, state that the maximum time is no more than 24h

There are only two situations to consider ： For example, the starting time is （7：20） The end time is (8:30)

The start time is equivalent to 7*60+20=（ The first ）440 minute , End time equivalent to 8*60+30=( The first )510 minute

After 510-440=70 minute namely 1 hour 10min

however , The number of minutes elapsed should be greater than 0, The premise is that the end time h Greater than the start time h

If the start time is (7:20) , So if the end time is （7：20） To （24：00） Within the scope of , Can be calculated in this way .

But if the end time falls on （0：00） To （7：20） That means the start time is from （7：20） After 24：00, Again from 0：00 Arrival end time , So the number of minutes actually elapsed

by （24*60-starttime The corresponding number of minutes ）+endtime The corresponding number of minutes

Sum up ： Time passed =endtime-starttime（ The corresponding number of minutes ） if endtime-starttime>=0

Time passed =1440-starttime+endtime( The corresponding number of minutes ) if endtiime-starttime<0

C++ 

#include <cstdio>
#include <iostream>
using namespace std;
int main(){
int a,b,c,d,starttime,endtime;
cin>>a>>b>>c>>d;
starttime=a*60+b;
endtime=c*60+d;
if (starttime<endtime) cout<<"O JOGO DUROU "<<(endtime-starttime)/60<<" HORA(S) E "<<(endtime-starttime)%60<<" MINUTO(S)";
else cout<<"O JOGO DUROU "<<(1440+endtime-starttime)/60<<" HORA(S) E "<<(1440+endtime-starttime)%60<<" MINUTO(S)";
}

python: Xiaozheng Sanxing solves the problem （ It's not recommended to write , There is no need to be short in order to highlight it , Not easy to understand but ）

a,b,c,d=map(int,input().strip().split())
start,end=a*60+b,c*60+d
print("O JOGO DUROU %d HORA(S) E %d MINUTO(S)"%((end-start)/60,(end-start)%60)) if start<end else print("O JOGO DUROU %d HORA(S) E %d MINUTO(S)"%((1440+end-start)/60,(end-start)%60))

  Recommend writing ： Writing clear step by step is good code

a,b,c,d=map(int,input().strip().split())
start=a*60+b
end=c*60+d
if start<end:
print("O JOGO DUROU %d HORA(S) E %d MINUTO(S)"%((end-start)/60,(end-start)%60))
else:
print("O JOGO DUROU %d HORA(S) E %d MINUTO(S)"%((1440+end-start)/60,(end-start)%60))

I'm Xiao Zheng I'm going to love mountains and seas ！