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Java中完成雙數組Trie樹實例

編輯：關於JAVA

Java中完成雙數組Trie樹實例。本站提示廣大學習愛好者：（Java中完成雙數組Trie樹實例）文章只能為提供參考，不一定能成為您想要的結果。以下是Java中完成雙數組Trie樹實例正文

傳統的Trie完成簡略，然則占用的空間其實是難以接收，特殊是當字符集不只限於英文26個字符的時刻，爆炸起來的空間基本沒法接收。

雙數組Trie就是優化了空間的Trie樹，道理本文就不講了，請參考An Efficient Implementation of Trie Structures，本法式的編寫也是參考這篇論文的。

關於幾點論文沒有說起的細節和與論文紛歧分歧的完成：

1.關於拔出字符串，假如有一個字符串是另外一個字符串的子串的話，我是將停止符也作為一條邊，發生一個新的結點，這個結點新節點的Base我置為0

所以一個字符串停止也有2中情形：一個是Base值為負，存儲殘剩字符(能夠只要一個停止符)到Tail數組；另外一個是Base為0。

所以在查詢的時刻要斟酌一下這兩種情形

2.關於第一種抵觸（論文中的Case 3），能夠要將Tail中的字符串掏出一部門，作為邊放到索引中。論文是應用將尾串左移的方法，我的方法直接修正Base值，而不是挪動尾串。

上面是java完成的代碼，可以處置雷同字符串拔出，子串的拔出等情形

/*
* Name: Double Array Trie
* Author: Yaguang Ding
* Mail: [email protected]
* Blog: blog.csdn.net/dingyaguang117
* Date: 2012/5/21
* Note: a word ends may be either of these two case:
* 1. Base[cur_p] == pos ( pos<0 and Tail[-pos] == 'END_CHAR' )
* 2. Check[Base[cur_p] + Code('END_CHAR')] == cur_p
*/

import java.util.ArrayList;
import java.util.HashMap;
import java.util.Map;
import java.util.Arrays;

public class DoubleArrayTrie {
final char END_CHAR = '\0';
final int DEFAULT_LEN = 1024;
int Base[] = new int [DEFAULT_LEN];
int Check[] = new int [DEFAULT_LEN];
char Tail[] = new char [DEFAULT_LEN];
int Pos = 1;
Map<Character ,Integer> CharMap = new HashMap<Character,Integer>();
ArrayList<Character> CharList = new ArrayList<Character>();

public DoubleArrayTrie()
{
  Base[1] = 1;

  CharMap.put(END_CHAR,1);
  CharList.add(END_CHAR);
  CharList.add(END_CHAR);
  for(int i=0;i<26;++i)
  {
   CharMap.put((char)('a'+i),CharMap.size()+1);
   CharList.add((char)('a'+i));
  }

}
private void Extend_Array()
{
  Base = Arrays.copyOf(Base, Base.length*2);
  Check = Arrays.copyOf(Check, Check.length*2);
}

private void Extend_Tail()
{
  Tail = Arrays.copyOf(Tail, Tail.length*2);
}

private int GetCharCode(char c)
{
  if (!CharMap.containsKey(c))
  {
   CharMap.put(c,CharMap.size()+1);
   CharList.add(c);
  }
  return CharMap.get(c);
}
private int CopyToTailArray(String s,int p)
{
  int _Pos = Pos;
  while(s.length()-p+1 > Tail.length-Pos)
  {
   Extend_Tail();
  }
  for(int i=p; i<s.length();++i)
  {
   Tail[_Pos] = s.charAt(i);
   _Pos++;
  }
  return _Pos;
}

private int x_check(Integer []set)
{
  for(int i=1; ; ++i)
  {
   boolean flag = true;
   for(int j=0;j<set.length;++j)
   {
    int cur_p = i+set[j];
    if(cur_p>= Base.length) Extend_Array();
    if(Base[cur_p]!= 0 || Check[cur_p]!= 0)
    {
     flag = false;
     break;
    }
   }
   if (flag) return i;
  }
}

private ArrayList<Integer> GetChildList(int p)
{
  ArrayList<Integer> ret = new ArrayList<Integer>();
  for(int i=1; i<=CharMap.size();++i)
  {
   if(Base[p]+i >= Check.length) break;
   if(Check[Base[p]+i] == p)
   {
    ret.add(i);
   }
  }
  return ret;
}

private boolean TailContainString(int start,String s2)
{
  for(int i=0;i<s2.length();++i)
  {
   if(s2.charAt(i) != Tail[i+start]) return false;
  }

  return true;
}
private boolean TailMatchString(int start,String s2)
{
  s2 += END_CHAR;
  for(int i=0;i<s2.length();++i)
  {
   if(s2.charAt(i) != Tail[i+start]) return false;
  }
  return true;
}

public void Insert(String s) throws Exception
{
  s += END_CHAR;

  int pre_p = 1;
  int cur_p;
  for(int i=0; i<s.length(); ++i)
  {
   //獲得狀況地位
   cur_p = Base[pre_p]+GetCharCode(s.charAt(i));
   //假如長度跨越現有，拓展數組
   if (cur_p >= Base.length) Extend_Array();

   //余暇狀況
   if(Base[cur_p] == 0 && Check[cur_p] == 0)
   {
    Base[cur_p] = -Pos;
    Check[cur_p] = pre_p;
    Pos = CopyToTailArray(s,i+1);
    break;
   }else
   //已存在狀況
   if(Base[cur_p] > 0 && Check[cur_p] == pre_p)
   {
    pre_p = cur_p;
    continue;
   }else
   //抵觸 1：碰到 Base[cur_p]小於0的，即碰到一個被緊縮存到Tail中的字符串
   if(Base[cur_p] < 0 && Check[cur_p] == pre_p)
   {
    int head = -Base[cur_p];

    if(s.charAt(i+1)== END_CHAR && Tail[head]==END_CHAR) //拔出反復字符串
    {
     break;
    }

    //公共字母的情形，由於上一個斷定曾經消除了卻束符，所以必定是2個都不是停止符
    if (Tail[head] == s.charAt(i+1))
    {
     int avail_base = x_check(new Integer[]{GetCharCode(s.charAt(i+1))});
     Base[cur_p] = avail_base;

     Check[avail_base+GetCharCode(s.charAt(i+1))] = cur_p;
     Base[avail_base+GetCharCode(s.charAt(i+1))] = -(head+1);
     pre_p = cur_p;
     continue;
    }
    else
    {
     //2個字母不雷同的情形，能夠有一個為停止符
     int avail_base ;
     avail_base = x_check(new Integer[]{GetCharCode(s.charAt(i+1)),GetCharCode(Tail[head])});

     Base[cur_p] = avail_base;

     Check[avail_base+GetCharCode(Tail[head])] = cur_p;
     Check[avail_base+GetCharCode(s.charAt(i+1))] = cur_p;

     //Tail 為END_FLAG 的情形
     if(Tail[head] == END_CHAR)
      Base[avail_base+GetCharCode(Tail[head])] = 0;
     else
      Base[avail_base+GetCharCode(Tail[head])] = -(head+1);
     if(s.charAt(i+1) == END_CHAR)
      Base[avail_base+GetCharCode(s.charAt(i+1))] = 0;
     else
      Base[avail_base+GetCharCode(s.charAt(i+1))] = -Pos;

     Pos = CopyToTailArray(s,i+2);
     break;
    }
   }else
   //抵觸2：以後結點曾經被占用，須要調劑pre的base
   if(Check[cur_p] != pre_p)
   {
    ArrayList<Integer> list1 = GetChildList(pre_p);
    int toBeAdjust;
    ArrayList<Integer> list = null;
    if(true)
    {
     toBeAdjust = pre_p;
     list = list1;
    }

    int origin_base = Base[toBeAdjust];
    list.add(GetCharCode(s.charAt(i)));
    int avail_base = x_check((Integer[])list.toArray(new Integer[list.size()]));
    list.remove(list.size()-1);

    Base[toBeAdjust] = avail_base;
    for(int j=0; j<list.size(); ++j)
    {
     //BUG
     int tmp1 = origin_base + list.get(j);
     int tmp2 = avail_base + list.get(j);

     Base[tmp2] = Base[tmp1];
     Check[tmp2] = Check[tmp1];

     //有後續
     if(Base[tmp1] > 0)
     {
      ArrayList<Integer> subsequence = GetChildList(tmp1);
      for(int k=0; k<subsequence.size(); ++k)
      {
       Check[Base[tmp1]+subsequence.get(k)] = tmp2;
      }
     }

     Base[tmp1] = 0;
     Check[tmp1] = 0;
    }

    //更新新的cur_p
    cur_p = Base[pre_p]+GetCharCode(s.charAt(i));

    if(s.charAt(i) == END_CHAR)
     Base[cur_p] = 0;
    else
     Base[cur_p] = -Pos;
    Check[cur_p] = pre_p;
    Pos = CopyToTailArray(s,i+1);
    break;
   }
  }
}

public boolean Exists(String word)
{
  int pre_p = 1;
  int cur_p = 0;

  for(int i=0;i<word.length();++i)
  {
   cur_p = Base[pre_p]+GetCharCode(word.charAt(i));
   if(Check[cur_p] != pre_p) return false;
   if(Base[cur_p] < 0)
   {
    if(TailMatchString(-Base[cur_p],word.substring(i+1)))
     return true;
    return false;
   }
   pre_p = cur_p;
  }
  if(Check[Base[cur_p]+GetCharCode(END_CHAR)] == cur_p)
   return true;
  return false;
}

//外部函數，前往婚配單詞的最靠後的Base index，
class FindStruct
{
  int p;
  String prefix="";
}
private FindStruct Find(String word)
{
  int pre_p = 1;
  int cur_p = 0;
  FindStruct fs = new FindStruct();
  for(int i=0;i<word.length();++i)
  {
   // BUG
   fs.prefix += word.charAt(i);
   cur_p = Base[pre_p]+GetCharCode(word.charAt(i));
   if(Check[cur_p] != pre_p)
   {
    fs.p = -1;
    return fs;
   }
   if(Base[cur_p] < 0)
   {
    if(TailContainString(-Base[cur_p],word.substring(i+1)))
    {
     fs.p = cur_p;
     return fs;
    }
    fs.p = -1;
    return fs;
   }
   pre_p = cur_p;
  }
  fs.p = cur_p;
  return fs;
}

public ArrayList<String> GetAllChildWord(int index)
{
  ArrayList<String> result = new ArrayList<String>();
  if(Base[index] == 0)
  {
   result.add("");
   return result;
  }
  if(Base[index] < 0)
  {
   String r="";
   for(int i=-Base[index];Tail[i]!=END_CHAR;++i)
   {
    r+= Tail[i];
   }
   result.add(r);
   return result;
  }
  for(int i=1;i<=CharMap.size();++i)
  {
   if(Check[Base[index]+i] == index)
   {
    for(String s:GetAllChildWord(Base[index]+i))
    {
     result.add(CharList.get(i)+s);
    }
    //result.addAll(GetAllChildWord(Base[index]+i));
   }
  }
  return result;
}

public ArrayList<String> FindAllWords(String word)
{
  ArrayList<String> result = new ArrayList<String>();
  String prefix = "";
  FindStruct fs = Find(word);
  int p = fs.p;
  if (p == -1) return result;
  if(Base[p]<0)
  {
   String r="";
   for(int i=-Base[p];Tail[i]!=END_CHAR;++i)
   {
    r+= Tail[i];
   }
   result.add(fs.prefix+r);
   return result;
  }

  if(Base[p] > 0)
  {
   ArrayList<String> r = GetAllChildWord(p);
   for(int i=0;i<r.size();++i)
   {
    r.set(i, fs.prefix+r.get(i));
   }
   return r;
  }

  return result;
}

}

測試代碼：

import java.io.BufferedReader;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Scanner;

import javax.xml.crypto.Data;

public class Main {

public static void main(String[] args) throws Exception {
  ArrayList<String> words = new ArrayList<String>();
  BufferedReader reader = new BufferedReader(new InputStreamReader(new FileInputStream("E:/兔子的實驗進修中間[課內]/ACM年夜賽/ACM第四屆校賽/E敕令提醒/words3.dic")));
  String s;
  int num = 0;
  while((s=reader.readLine()) != null)
  {
   words.add(s);
   num ++;
  }
  DoubleArrayTrie dat = new DoubleArrayTrie();

  for(String word: words)
  {
   dat.Insert(word);
  }

  System.out.println(dat.Base.length);
  System.out.println(dat.Tail.length);

  Scanner sc = new Scanner(System.in);
  while(sc.hasNext())
  {
   String word = sc.next();
   System.out.println(dat.Exists(word));
   System.out.println(dat.FindAllWords(word));
  }

}