Java上鉤算時光差的辦法。本站提示廣大學習愛好者:(Java上鉤算時光差的辦法)文章只能為提供參考,不一定能成為您想要的結果。以下是Java上鉤算時光差的辦法正文
本文實例講述了Java上鉤算時光差的辦法。分享給年夜家供年夜家參考。詳細以下:
假定如今是2004-03-26 13:31:40
曩昔是:2004-01-02 11:30:24
要取得兩個日期差,差的情勢為:XX天XX小時XX分XX秒
辦法一:
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); try { Date d1 = df.parse("2004-03-26 13:31:40"); Date d2 = df.parse("2004-01-02 11:30:24"); long diff = d1.getTime() - d2.getTime(); long days = diff / (1000 * 60 * 60 * 24); } catch (Exception e) { }
辦法二:
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); java.util.Date now = df.parse("2004-03-26 13:31:40"); java.util.Date date=df.parse("2004-01-02 11:30:24"); long l=now.getTime()-date.getTime(); long day=l/(24*60*60*1000); long hour=(l/(60*60*1000)-day*24); long min=((l/(60*1000))-day*24*60-hour*60); long s=(l/1000-day*24*60*60-hour*60*60-min*60); System.out.println(""+day+"天"+hour+"小時"+min+"分"+s+"秒");
辦法三:
SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); java.util.Date begin=dfs.parse("2004-01-02 11:30:24"); java.util.Date end = dfs.parse("2004-03-26 13:31:40"); long between=(end.getTime()-begin.getTime())/1000; //除以1000是為了轉換成秒 long day1=between/(24*3600); long hour1=between%(24*3600)/3600; long minute1=between%3600/60; long second1=between%60/60; System.out.println(""+day1+"天"+hour1+"小時"+minute1+"分"+second1+"秒");
願望本文所述對年夜家的java法式設計有所贊助。