今天找到一個utf-8編碼轉換成gb2312編碼的ASP函數，能給大家解決這塊問題的時候省不少事了。
代碼如下:
<%
'用途:將UTF-8編碼漢字轉換為GB2312編碼，兼容英文和數字
'版權:雖說是原創，其實也參考別人的部分算法
'用法:Response.write UTF2GB("%E9%83%BD%E5%B8%82%E6%83%85%E7%B7%A3 %E6%98%9F%E5%BA%A7")
function UTF2GB(UTFStr)
for Dig=1 to len(UTFStr)
if mid(UTFStr,Dig,1)="%" then
if len(UTFStr) >= Dig+8 then
GBStr=GBStr & ConvChinese(mid(UTFStr,Dig,9))
Dig=Dig+8
else
GBStr=GBStr & mid(UTFStr,Dig,1)
end if
else
GBStr=GBStr & mid(UTFStr,Dig,1)
end if
next
UTF2GB=GBStr
end function
function ConvChinese(x)
A=split(mid(x,2),"%")
i=0
j=0
for i=0 to ubound(A)
A(i)=c16to2(A(i))
next
for i=0 to ubound(A)-1
DigS=instr(A(i),"0")
Unicode=""
for j=1 to DigS-1
if j=1 then
A(i)=right(A(i),len(A(i))-DigS)
Unicode=Unicode & A(i)
else
i=i+1
A(i)=right(A(i),len(A(i))-2)
Unicode=Unicode & A(i)
end if
next
if len(c2to16(Unicode))=4 then
ConvChinese=ConvChinese & chrw(int("&H" & c2to16(Unicode)))
else
ConvChinese=ConvChinese & chr(int("&H" & c2to16(Unicode)))
end if
next
end function
function c2to16(x)
i=1
for i=1 to len(x) step 4
c2to16=c2to16 & hex(c2to10(mid(x,i,4)))
next
end function
function c2to10(x)
c2to10=0
if x="0" then exit function
i=0
for i= 0 to len(x) -1
if mid(x,len(x)-i,1)="1" then c2to10=c2to10+2^(i)
next
end function
function c16to2(x)
i=0
for i=1 to len(trim(x))
tempstr= c10to2(cint(int("&h" & mid(x,i,1))))
do while len(tempstr)<4
tempstr="0" & tempstr
loop
c16to2=c16to2 & tempstr
next
end function
function c10to2(x)
mysign=sgn(x)
x=abs(x)
DigS=1
do
if x<2^DigS then
exit do
else
DigS=DigS+1
end if
loop
tempnum=x
i=0
for i=DigS to 1 step-1
if tempnum>=2^(i-1) then
tempnum=tempnum-2^(i-1)
c10to2=c10to2 & "1"
else
c10to2=c10to2 & "0"
end if
next
if mysign=-1 then c10to2="-" & c10to2
end function
%>
