今天 在開發時碰到了關於Parse error: syntax error, unexpected $end 錯誤 提示，根據自己 的要驗這裡可能是 if else未成對出現，下面我們來總結一下問題和解決辦法。
也許是不熟悉的php的一些特性吧，不過寫多了，也就慢慢適應將就了.....
這裡就整理一個代碼編寫調試問題，錯誤如下：
Parse error: syntax error, unexpected $end in D:xampphtdocsguestBookguestBook.php on line 330
看看程序 330行，代碼最後一行，這有什麼錯誤？google搜，找到了：
In PHP 5, the following error may appears as an error entry in Apache error log or simply displays on PHP web page, even if calling to php scripts with php_info() works perfectly and successfully returns information on PHP configurations:
Parse Error: syntax error, unexpected $end in ….. scripts.php on line …
The error may caused by a missing curly bracket in PHP script coding. Beside, it may also caused by error in PHP coding in class definition, as in PHP, a class definition cannot be broke up and distributed into multiple files, or into multiple PHP blocks, unless the break is within a method declaration.
But more commonly, the error is often caused by the use of Short Open tags in PHP,
To use short open tags, it must be enabled in PHP.INI. Search for short_open_tag in PHP.INI, and change the value to On. The line should look line:
short_open_tag = On
欺我英文不好啊？看看其它幾條搜索，都沒說到點子上，那就看看英文了，雖不能如數翻譯，大致意思是瞧明白了：
錯誤發生是使用了短標簽，可以在php.ini中設置short_open_tag = On
原來Parse error 提示一般是 語法錯誤,使用了開放的標簽，語句沒有結束 也就是編程基本的一些錯, 比如沒注意 語句結束加 ";" 或者 if(){...} 後面忘了"}" ；<?php...?>忘了"?>"。仔細檢查代碼，果然是一處漏掉了"}"，修改程序正常運行
實例
conn.php
<?php
/*
* bkJiaJob v1.0
* Programmer : Msn/QQ [email protected] (925939)
* www.php100.com Develop a project PHP - MySQL - Apache
* Window 2003 - Preferences - PHPeclipse - PHP - Code Templates
*/
$conn = @ mysql_connect("localhost", "root", "dong") or die("數據庫鏈接錯誤");
mysql_select_db("news", $conn);
mysql_query("set names 'GBK'"); //使用GBK中文編碼;
function htmtocode($content) {
$content = str_replace("n", "<br>", str_replace(" ", " ", $content));
return $content;
}
//$content=str_replace("'","‘",$content);
//htmlspecialchars();
?>
<?php
/*
* bkJiaJob v1.0
* Programmer : Msn/QQ [email protected] (925939)
* www.php100.com Develop a project PHP - MySQL - Apache
* Window 2003 - Preferences - PHPeclipse - PHP - Code Templates
*/
include("conn.php");
include("head.php");
$SQL="SELECT * FROM `message` order by id desc";
$query=mysql_query($SQL);
while($row=mysql_fetch_array($query)){
?>
<table width=500 border="0" cellpadding="5" cellspacing="1" bgcolor="#add3ef">
<tr bgcolor="#eff3ff">
<td>標題：<?=$row[title]?> 用戶：<?=$row[user]?></td>
</tr>
<tr bgColor="#ffffff">
<td>內容：<?
echo htmtocode($row[content]);
?></td>
</tr>
</table>
<?
}
?>
運行出現下邊的錯誤
Parse error: syntax error, unexpected $end in E:wampwwwleave_messagelist.php on line 35
報錯的原因在這裡
<?
}
?>
改成
<?php
}
?>
解決 辦法
你把標題、內容，用戶那三個改成<?php echo $row['title'];?>這樣的就行了啊。函數就<?php echo htmtocode($row[content]); ?>
這不是主要的，至多只是顯示不出數據
報錯的原因在這裡
<?
}
?>
改成
<?php
}
?>
