PHP獲得跳轉的真實地址實例

現在有很多的短網址應用，點擊就跳轉到縮短之前的網址了，那今天我們就來看一下，PHP如何獲取短網址跳轉之前的網址，其實也很簡單，就是用php的get_headers 函數，

取得Response Headers，之後慢慢分析就行了。

給出具體實現方法：

$header = get_headers($url, 1);
if (strpos($header[0], ’301′) || strpos($header[0], ’302′)) {
if (is_array($header['Location'])) {
return $header['Location'][count($header['Location'])-1];
} else {
return $header['Location'];
}
} else {
return $url;
}

實例二

<?php
//
echo get_redirect_url('http://www.111cN.nEt');
//輸出結果為：http://code.google.com/android/
function get_redirect_url($url){
    $redirect_url = null;

    $url_parts = @parse_url($url);
    if (!$url_parts) return false;
    if (!isset($url_parts['host'])) return false; //can't process relative URLs
    if (!isset($url_parts['path'])) $url_parts['path'] = '/';

    $sock = fsockopen($url_parts['host'], (isset($url_parts['port']) ? (int)$url_parts['port'] : 80), $errno, $errstr, 30);
    if (!$sock) return false;

    $request = "HEAD " . $url_parts['path'] . (isset($url_parts['query']) ? '?'.$url_parts['query'] : '') . " HTTP/1.1rn";
    $request .= 'Host: ' . $url_parts['host'] . "rn";
    $request .= "Connection: Closernrn";
    fwrite($sock, $request);
    $response = '';
    while(!feof($sock)) $response .= fread($sock, 8192);
    fclose($sock);

    if (preg_match('/^Location: (.+?)$/m', $response, $matches)){
        if ( substr($matches[1], 0, 1) == "/" )
            return $url_parts['scheme'] . "://" . $url_parts['host'] . trim($matches[1]);
        else
            return trim($matches[1]);

    } else {
        return false;
    }

}