程式師世界 >> 編程語言 >> 網頁編程 >> PHP編程 >> 關於PHP編程 >> php calender(日歷)二個版本代碼示例(解決2038問題)

php calender(日歷)二個版本代碼示例(解決2038問題)

編輯：關於PHP編程

注意32位機有2038問題，所以32位服務器的年限范圍1970年~2038年

我們還可以使用DateTime來規避這個問題(這樣與32位64位無關了)

復制代碼代碼如下:
<?php
/**
*
* 我的日歷
* date_default_timezone_set date mktime
* @param int $year
* @param int $month
* @param string $timezone
* @author fc_lamp
* @blog: fc-lamp.blog.163.com
*/
function myCalender($year = '', $month = '', $timezone = 'Asia/Shanghai')
{

date_default_timezone_set ( $timezone );
$year = abs ( intval ( $year ) );
$month = abs ( intval ( $month ) );

//是否是32位機
if (is32())
{
  if ($year < 1970 or $year >= 2038)
  {
   $year = date ( 'Y' );
  }
} else
{
  if ($year <= 0)
  {
   $year = date ( 'Y' );
  }

}

if ($month <= 0 or $month > 12)
{
  $month = date ( 'm' );
}

//上一年
$pretYear = $year - 1;
//上一月
$mpYear = $year;
$preMonth = $month - 1;
if ($preMonth <= 0)
{
  $preMonth = 1;
  $mpYear = $pretYear;
}

//下一年
$nextYear = $year + 1;
//下一月
$mnYear = $year;
$nextMonth = $month + 1;
if ($nextMonth > 12)
{
  $nextMonth = 1;
  $mnYear = $nextYear;
}

//日歷頭
$html = <<<HTML
<table width="500" border="1">
<tr align="center">
    <td><a href="?y=$pretYear">上一年</a></td>
    <td><a href="?y=$mpYear&m=$preMonth">上一月</a></td>
     <td><a href="?">回到今天</a></td>
    <td><a href="?y=$mnYear&m=$nextMonth">下一月</a></td>
<td><a href="?y=$nextYear">下一年</a></td>
</tr>
<tr align="center">
    <td colspan="5">{$year}年{$month}月</td>
</tr>
<tr>
<td colspan="5">
  <table width="100%" border="1">
   <tr align="center">
    <td >星期一</td>
    <td >星期二</td>
    <td >星期三</td>
    <td >星期四</td>
    <td >星期五</td>
    <td >星期六</td>
    <td >星期天</td>
   </tr>
HTML;

$currentDay = date ( 'Y-m-j' );

//當月最後一天
$lastday = date ( 'j', mktime ( 0, 0, 0, $nextMonth, 0, $year ) );

//循環輸出天數
$day = 1;
$line = '';
while ( $day <= $lastday )
{
  $cday = $year . '-' . $month . '-' . $day;

  //當前星期幾
  $nowWeek = date ( 'N', mktime ( 0, 0, 0, $month, $day, $year ) );

  if ($day == 1)
  {
   $line = '<tr align="center">';
   $line .= str_repeat ( '<td> </td>', $nowWeek - 1 );
  }

  if ($cday == $currentDay)
  {
   $style = '';
  } else
  {
   $style = '';
  }

  $line .= "<td $style>$day</td>";

  //一周結束
  if ($nowWeek == 7)
  {
   $line .= '</tr>';
   $html .= $line;
   $line = '<tr align="center">';
  }

  //全月結束
  if ($day == $lastday)
  {
   if ($nowWeek != 7)
   {
    $line .= str_repeat ( '<td> </td>', 7 - $nowWeek );
   }
   $line .= '</tr>';
   $html .= $line;

   break;
  }

  $day ++;
}

$html .= <<<HTML
  </table>
</td>
</tr>
</table>
HTML;
return $html;
}

/**
*
* 檢測是否是32位機
* @author fc_lamp
* @blog: fc-lamp.blog.163.com
*/
function is32()
{
$is32 = False;
if (strtotime ( '2039-10-10' ) === False)
{
$is32 = True;
}
return $is32;
}

使用DateTime 類解決2038問題，這樣不分32位與64位，代碼如下：

復制代碼代碼如下:
<?php
/**
*
* 我的日歷(DateTime版本)
* date_default_timezone_set date mktime
* @param int $year
* @param int $month
* @param string $timezone
* @author fc_lamp
* @blog: fc-lamp.blog.163.com
*/
function myCalender($year = '', $month = '', $timezone = 'Asia/Shanghai')
{

date_default_timezone_set ( $timezone );
$year = abs ( intval ( $year ) );
$month = abs ( intval ( $month ) );

$nowDate = new DateTime();

if ($year <= 0)
{
  $year = $nowDate->format( 'Y' );
}

if ($month <= 0 or $month > 12)
{
  $month = $nowDate->format('m' );
}

//上一年
$pretYear = $year - 1;
//上一月
$mpYear = $year;
$preMonth = $month - 1;
if ($preMonth <= 0)
{
  $preMonth = 1;
  $mpYear = $pretYear;
}

//下一年
$nextYear = $year + 1;
//下一月
$mnYear = $year;
$nextMonth = $month + 1;
if ($nextMonth > 12)
{
  $nextMonth = 1;
  $mnYear = $nextYear;
}

//日歷頭
$html = <<<HTML
<table width="500" border="1">
<tr align="center">
    <td><a href="?y=$pretYear">上一年</a></td>
    <td><a href="?y=$mpYear&m=$preMonth">上一月</a></td>
     <td><a href="?">回到今天</a></td>
    <td><a href="?y=$mnYear&m=$nextMonth">下一月</a></td>
<td><a href="?y=$nextYear">下一年</a></td>
</tr>
<tr align="center">
    <td colspan="5">{$year}年{$month}月</td>
</tr>
<tr>
<td colspan="5">
  <table width="100%" border="1">
   <tr align="center">
    <td >星期一</td>
    <td >星期二</td>
    <td >星期三</td>
    <td >星期四</td>
    <td >星期五</td>
    <td >星期六</td>
    <td >星期天</td>
   </tr>
HTML;

$currentDay = $nowDate->format('Y-m-j' );

//當月最後一天
$creatDate = new DateTime("$year-$nextMonth-0");
$lastday = $creatDate->format('j');
$creatDate = NULL;

//循環輸出天數
$day = 1;
$line = '';
while ( $day <= $lastday )
{
  $cday = $year . '-' . $month . '-' . $day;

  //當前星期幾
  $creatDate = new DateTime("$year-$month-$day");
  $nowWeek = $creatDate->format('N');
  $creatDate = NULL;

  if ($day == 1)
  {
   $line = '<tr align="center">';
   $line .= str_repeat ( '<td> </td>', $nowWeek - 1 );
  }

  if ($cday == $currentDay)
  {
   $style = '';
  } else
  {
   $style = '';
  }

  $line .= "<td $style>$day</td>";

  //一周結束
  if ($nowWeek == 7)
  {
   $line .= '</tr>';
   $html .= $line;
   $line = '<tr align="center">';
  }

  //全月結束
  if ($day == $lastday)
  {
   if ($nowWeek != 7)
   {
    $line .= str_repeat ( '<td> </td>', 7 - $nowWeek );
   }
   $line .= '</tr>';
   $html .= $line;

   break;
  }

  $day ++;
}

$html .= <<<HTML
  </table>
</td>
</tr>
</table>
HTML;
return $html;
}