這篇文章主要介紹了php上傳文件並存儲到mysql數據庫的方法,以完整實例形式較為詳細的分析了php操作文件上傳與數據庫存儲的技巧,具有一定參考借鑒價值,需要的朋友可以參考下
本文實例講述了php上傳文件並存儲到mysql數據庫的方法。分享給大家供大家參考。具體分析如下：
下面的代碼分別用於創建mysql表和上傳文件保存到mysql數據庫
創建mysql表：
? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 <?php $con = mysql_connect("localhost", "", ""); mysql_select_db("w3m"); $sql = "CREATE TABLE updfiles (" . " id INTEGER NOT NULL AUTO_INCREMENT" . ", name VARCHAR(80) NOT NULL" . ", type VARCHAR(80) NOT NULL" . ", size INTEGER NOT NULL" . ", content BLOB" . ", PRIMARY KEY (id)" . ")"; mysql_query($sql, $con); mysql_close($con); ?>上傳文件並保存到mysql中，通過insert語句插入
? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 <?php $con = mysql_connect("localhost", "", ""); mysql_select_db("w3m"); $error = $_FILES['w3img']['error']; $tmp_name = $_FILES['w3img']['tmp_name']; $size = $_FILES['w3img']['size']; $name = $_FILES['w3img']['name']; $type = $_FILES['w3img']['type']; print("n"); if ($error == UPLOAD_ERR_OK && $size > 0) { $fp = fopen($tmp_name, 'r'); $content = fread($fp, $size); fclose($fp); $content = addslashes($content); $sql = "INSERT INTO fyi_files (name, type, size, content)" . " VALUES ('$name', '$type', $size, '$content')"; mysql_query($sql, $con); print("File stored.n"); } else { print("Database Save for upload failed.n"); } print("n"); mysql_close($con); ?>希望本文所述對大家的php程序設計有所幫助。
