PHP將二維數組某一個字段相同的數組合並起來的方法

本文實例講述了PHP將二維數組某一個字段相同的數組合並起來的方法。分享給大家供大家參考，具體如下：

例子：

array(3) {
 [0]=>
 array(16) {
  ["id"]=>
  string(2) "42"
  ["uid"]=>
  string(2) "14"
  ["euid"]=>
  string(2) "56"
  ["did"]=>
  string(1) "1"
  ["nid"]=>
  string(1) "0"
  ["phonetime"]=>
  string(10) "1443927600"
  ["createtime"]=>
  string(10) "1443880619"
  ["type"]=>
  string(1) "3"
  ["status"]=>
  string(1) "0"
  ["atype"]=>
  string(1) "1"
  ["mtype"]=>
  string(1) "2"
  ["endtime"]=>
  string(1) "0"
  ["time"]=>
  string(10) "10月04日"
  ["date"]=>
  string(6) "周日"
  ["uname"]=>
  NULL
  ["album"]=>
  string(0) ""
 }
 [1]=>
 array(16) {
  ["id"]=>
  string(2) "40"
  ["uid"]=>
  string(2) "14"
  ["euid"]=>
  string(2) "56"
  ["did"]=>
  string(1) "1"
  ["nid"]=>
  string(1) "0"
  ["phonetime"]=>
  string(10) "1444359600"
  ["createtime"]=>
  string(10) "1444268595"
  ["type"]=>
  string(1) "3"
  ["status"]=>
  string(1) "0"
  ["atype"]=>
  string(1) "1"
  ["mtype"]=>
  string(1) "2"
  ["endtime"]=>
  string(1) "0"
  ["time"]=>
  string(10) "10月09日"
  ["date"]=>
  string(6) "周五"
  ["uname"]=>
  NULL
  ["album"]=>
  string(0) ""
 }
 [2]=>
 array(16) {
  ["id"]=>
  string(2) "43"
  ["uid"]=>
  string(1) "2"
  ["euid"]=>
  string(2) "56"
  ["did"]=>
  string(1) "1"
  ["nid"]=>
  string(1) "0"
  ["phonetime"]=>
  string(10) "1444359620"
  ["createtime"]=>
  string(10) "1444268595"
  ["type"]=>
  string(1) "3"
  ["status"]=>
  string(1) "0"
  ["atype"]=>
  string(1) "1"
  ["mtype"]=>
  string(1) "2"
  ["endtime"]=>
  string(1) "0"
  ["time"]=>
  string(10) "10月09日"
  ["date"]=>
  string(6) "周五"
  ["uname"]=>
  NULL
  ["album"]=>
  string(0) ""
 }
}

現在想要對這個二維數組下的元素，time相同的合並到同一數組下。想要的效果為：

array(2) {
 ["10月04日"]=>
 array(1) {
  [0]=>
  array(16) {
   ["id"]=>
   string(2) "42"
   ["uid"]=>
   string(2) "14"
   ["euid"]=>
   string(2) "56"
   ["did"]=>
   string(1) "1"
   ["nid"]=>
   string(1) "0"
   ["phonetime"]=>
   string(10) "1443927600"
   ["createtime"]=>
   string(10) "1443880619"
   ["type"]=>
   string(1) "3"
   ["status"]=>
   string(1) "0"
   ["atype"]=>
   string(1) "1"
   ["mtype"]=>
   string(1) "2"
   ["endtime"]=>
   string(1) "0"
   ["time"]=>
   string(10) "10月04日"
   ["date"]=>
   string(6) "周日"
   ["uname"]=>
   NULL
   ["album"]=>
   string(0) ""
  }
 }
 ["10月09日"]=>
 array(2) {
  [0]=>
  array(16) {
   ["id"]=>
   string(2) "40"
   ["uid"]=>
   string(2) "14"
   ["euid"]=>
   string(2) "56"
   ["did"]=>
   string(1) "1"
   ["nid"]=>
   string(1) "0"
   ["phonetime"]=>
   string(10) "1444359600"
   ["createtime"]=>
   string(10) "1444268595"
   ["type"]=>
   string(1) "3"
   ["status"]=>
   string(1) "0"
   ["atype"]=>
   string(1) "1"
   ["mtype"]=>
   string(1) "2"
   ["endtime"]=>
   string(1) "0"
   ["time"]=>
   string(10) "10月09日"
   ["date"]=>
   string(6) "周五"
   ["uname"]=>
   NULL
   ["album"]=>
   string(0) ""
  }
  [1]=>
  array(16) {
   ["id"]=>
   string(2) "43"
   ["uid"]=>
   string(1) "2"
   ["euid"]=>
   string(2) "56"
   ["did"]=>
   string(1) "1"
   ["nid"]=>
   string(1) "0"
   ["phonetime"]=>
   string(10) "1444359620"
   ["createtime"]=>
   string(10) "1444268595"
   ["type"]=>
   string(1) "3"
   ["status"]=>
   string(1) "0"
   ["atype"]=>
   string(1) "1"
   ["mtype"]=>
   string(1) "2"
   ["endtime"]=>
   string(1) "0"
   ["time"]=>
   string(10) "10月09日"
   ["date"]=>
   string(6) "周五"
   ["uname"]=>
   NULL
   ["album"]=>
   string(0) ""
  }
 }
}

那麼。。。代碼很簡單，沒有想象的那麼復雜，想要的結果是個三維數組

$result 為原二維數組

$res = array(); //想要的結果
foreach ($result as $k => $v) {
  $res[$v['time']][] = $v;
}

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希望本文所述對大家PHP程序設計有所幫助。