最近接了一個項目，其中有一需求是用php獲取一年有幾周以及每周開始日期和接觸日期。在網上找些資料沒有合適的，於是自己做了一份，下面通過兩種方式實現PHP獲取一年有幾周以及每周開始日期和結束日期
代碼一：
<?php
header("Content-type:text/html;charset=utf-8");
date_default_timezone_set("Asia/Shanghai");
$year = (int)$_GET['year'];
$week = (int)$_GET['week'];
$weeks = date("W", mktime(0, 0, 0, 12, 28, $year));
echo $year . '年一共有' . $weeks . '周<br />';
if ($week > $weeks || $week <= 0)
{
$week = 1;
}
if ($week < 10)
{
$week = '0' . $week;
}
$timestamp['start'] = strtotime($year . 'W' . $week);
$timestamp['end'] = strtotime('+1 week -1 day', $timestamp['start']);
echo $year . '年第' . $week . '周開始時間戳：' . $timestamp['start'] . '<br />';
echo $year . '年第' . $week . '周結束時間戳：' . $timestamp['end'] . '<br />';
echo $year . '年第' . $week . '周開始日期：' . date("Y-m-d", $timestamp['start']) . '<br />';
echo $year . '年第' . $week . '周結束日期：' . date("Y-m-d", $timestamp['end']);
?>
代碼二：
<?php
header("Content-type:text/html;charset=utf-8");
function getIsoWeeksInYear($year)
{
$date = new DateTime;
$date->setISODate($year, 53);
return ($date->format("W") === "53" ? 53 : 52);
}
function weekday($custom_date)
{
$week_start = date('d-m-Y', strtotime('this week monday', $custom_date));
$week_end = date('d-m-Y', strtotime('this week sunday', $custom_date));
$week_array[0] = $week_start;
$week_array[1] = $week_end;
return $week_array;
}
echo '<br> Weeks in 2013<br>' . getIsoWeeksInYear(2013);
$weekday = weekday(strtotime(date('d-m-Y', strtotime('5-8-2013'))));
echo '<br> 10-8-2013';
echo '<br>Start: ' . $weekday[0];
echo '<br>End: ' . $weekday[1];
?>
以上本文的全部內容，希望對大家學習PHP獲取一年有幾周以及每周開始日期和結束日期，有所幫助。
