php上傳圖片客戶端和服務器端實現方法

本文實例講述了php上傳圖片客戶端和服務器端實現方法。分享給大家供大家參考。具體如下：

前台表單代碼

<form name="form1" method="post" action="admin_upfile.php" enctype="multipart/form-data">
  <input type="file" name="pic">
  <input type="submit" name="Submit" value="開始上傳" class="button">
</form>

後端php代碼

<?php
//這裡上傳 $upsize判斷上傳文件的大小
$uppath = "/attached/"; //文件上傳路徑
//轉換根目錄的路徑
if (strpos($uppath, "/") == 0)
{
  $i = 0;
  $thpath = $_SERVER["SCRIPT_NAME"];
  $thpath = substr($thpath, 1, strlen($thpath));
  while (strripos($thpath, "/") !== false)
  {
 $thpath = substr($thpath, strpos($thpath, "/") + 1, strlen($thpath));
 $i = ++$i;
  }
  $pp = "";
  for ($j = 0; $j < $i; ++$j)
  {
 $pp .= "../";
  }
  $uppaths = $pp . substr($uppath, 1, strlen($thpath));
}
$filename = date("y-m-d");
if (is_dir($uppaths . $filename) != TRUE)
  mkdir($uppaths . $filename, 0777);
$f = $_FILES['pic'];
if ($f["type"] != "image/gif" && $f["type"] != "image/pjpeg" && $f["type"] != "image/jpeg" && $f["type"] != "image/x-png")
{
  echo "<script>alert('只能上傳圖片格式的文件');window.close()</script>";
  return false;
}
//獲得文件擴展名
$temp_arr = explode(".", $f["name"]);
$file_ext = array_pop($temp_arr);
$file_ext = trim($file_ext);
$file_ext = strtolower($file_ext);
//新文件名
$new_file_name = md5(date("YmdHis")) . '.' . $file_ext;
echo $dest = $uppaths . $filename . "/" . date("ymdhis") . "_" . 
$new_file_name; //設置文件名為日期加上文件名避免重復 上傳目錄
echo $dest1 = $uppath . $filename . "/" . date("ymdhis") . "_" . 
$new_file_name; //設置文件名為日期加上文件名避免重復
$r = move_uploaded_file($f['tmp_name'], $dest);
?>

希望本文所述對大家的php程序設計有所幫助。