php判斷正常訪問和外部訪問
復制代碼 代碼如下:
<?php
session_start();
if(isset($_POST['check'])&&!empty($_POST['name'])){
if($_POST['check'] == $_SESSION['check']){
echo "正常訪問";
}else{
echo "外部訪問";
}
}
$token = md5(uniqid(rand(),true));
$_SESSION['check'] = $token;
?>
<form method="post" action="">
<input type="text" name="name"/>
<input type="text" name="check" value="<?=$token;?>">
<input type="submit">
