php抓取https的內容的代碼

直接用file_get_contents，會報錯；

復制代碼 代碼如下:
$url = (https://xxx.com");
file_get_contents($url);

錯誤：
Warning: file_get_contents(https://xxx.com) [function.file-get-contents]: failed to open stream: No such file or directory in D:wampwwwgrabber_clientindex.php on line 3

用curl的方式是可以的：
復制代碼 代碼如下:
$url = (https://xxx.com);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$url);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, false);
$result = curl_exec($ch);
print_r($result);
?>

重點是以下兩句：
復制代碼 代碼如下:
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, false);