MySQL 刪除數據庫中重復數據方法小結

剛開始，根據我的想法，這個很簡單嘛，上sql語句

delete from zqzrdp where tel in (select min(dpxx_id) from zqzrdp group by tel having count(tel)>1);

執行，報錯！！~！~

異常意為：你不能指定目標表的更新在FROM子句。傻了，MySQL 這樣寫，不行，讓人郁悶。

難倒只能分步操作，蛋疼

以下是網友寫的，同樣是坑爹的代碼，我機器上運行不了。

1. 查詢需要刪除的記錄，會保留一條記錄。

select a.id,a.subject,a.RECEIVER from test1 a left join (select c.subject,c.RECEIVER ,max(c.id) as bid from test1 c where status=0 GROUP BY RECEIVER,SUBJECT having count(1) >1) b on a.id< b.bid where a.subject=b.subject and a.RECEIVER = b.RECEIVER and a.id < b.bid

2. 刪除重復記錄，只保留一條記錄。注意，subject,RECEIVER 要索引，否則會很慢的。

delete a from test1 a, (select c.subject,c.RECEIVER ,max(c.id) as bid from test1 c where status=0 GROUP BY RECEIVER,SUBJECT having count(1) >1) b where a.subject=b.subject and a.RECEIVER = b.RECEIVER and a.id < b.bid;

3. 查找表中多余的重復記錄，重復記錄是根據單個字段（peopleId）來判斷

select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)

4. 刪除表中多余的重復記錄，重復記錄是根據單個字段（peopleId）來判斷，只留有rowid最小的記錄

delete from people where peopleId in (select peopleId from people group by peopleId  having count(peopleId) > 1) and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)

5.刪除表中多余的重復記錄（多個字段），只留有rowid最小的記錄

delete from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

看來想偷懶使用一句命令完成這個事好像不太顯示，還是老老實實的分步處理吧，思路先建立復制一個臨時表，然後對比臨時表內的數據，刪除主表裡的數據

alter table tableName add autoID int auto_increment not null; 

create table tmp select min(autoID) as autoID from tableName group by Name,Address; 

create table tmp2 select tableName.* from tableName,tmp where tableName.autoID = tmp.autoID; 

drop table tableName; 

rename table tmp2 to tableName;