工作中遇到一個問題:要更新一個數據表。
這個表是我自己創建的,有7個字段,id、name、package等等
創建的時候,因為我把name、package的信息分別存在兩個文本文件中,
所以我就用Insert方法,一次性將所有的name插入數據庫中。
name全部導入數據庫中了,但是我的package沒有導入,這時我仍然想用insert的方法插入,但是不行。
這時候應該利用update的方法。一次更新多條信息的思路如下:
UPDATE table_name SET field_name = CASE other_field WHEN 1 THEN 'value' WHEN 2 THEN 'value' WHEN 3 THEN 'value' END WHERE id IN (1,2,3) 測試代碼如下: <?php /* *function: insert app's apk ,logo_url, document_title,app_desc,package_name * into talbe atable use database db . */ //connect database catx. $server='localhost'; $user='root'; $passwd='root'; $port='3306'; $dbname='catx'; $link=mysql_connect($server,$user,$passwd); if (!$link) { die('Could not connect: ' . mysql_error()); } else echo "Connected successfully\n"; mysql_select_db("db",$link); //set init variable and start time $st=microtime_float(); $table="pydot_g"; $path = "txt"; $fname_package_name = "package_name.txt"; // $handle= @fopen($path."/".$fname_package_name, "r"); $i=1; $sql = "UPDATE pydot_g SET package_name = CASE id "; $ids=""; while(($buf[$i]=fgets($handle,512))!==false){ $sql .= sprintf("WHEN %d THEN '%s' ", $i, $buf[$i]); // 拼接SQL語句 $ids .= sprintf("%d,",$i); $i++; } //$ids=implode(',',$ids); $ids.=$i; $sql .= "END WHERE id IN ($ids)"; echo $sql; mysql_query($sql); fclose($handle); mysql_close($link); //echo the results and total time used $et=microtime_float(); $t=$et-$st; echo "\r\ninsert into talbe ",$table," ",$i,"times;\r\n"; echo "Total time $t seconds.\r\n"; //function calculate time ,return a float number function microtime_float(){ list($usec, $sec) = explode(" ", microtime()); return ((float)$usec + (float)$sec); } ?>