mysql查詢當天的所有信息：
代碼如下
select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())
這個有一些繁瑣，還有簡單的寫法：
代碼如下
select * from table where date(regdate) = curdate();
另一種寫法沒測試過
查詢當天的記錄
代碼如下
select * from hb_article_view where TO_DAYS(hb_AddTime) = TO_DAYS(NOW())
date()函數獲取日期部分, 扔掉時間部分，然後與當前日期比較即可
補充：本周、上周、本月、上個月份的數據
查詢當前這周的數據
代碼如下
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());
查詢上周的數據
代碼如下
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;
查詢當前月份的數據
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')
查詢距離當前現在6個月的數據
代碼如下
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
查詢上個月的數據
代碼如下
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')
select * from `user` where DATE_FORMAT(pudate,'%Y%m') = DATE_FORMAT(CURDATE(),'%Y%m') ;
select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())
select *
from user
where MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now())
select *
from [user]
where YEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = YEAR(now())
and MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now())
select *
from [user]
where pudate between 上月最後一天
and 下月第一天
mysql查詢多少秒內的數據
代碼如下
SELECT count( * ) AS c, sum( if( logusertype =2, logusertype, 0 ) ) /2 AS a, sum( if( logusertype =3, logusertype, 0 ) ) /3 AS b
FROM testlog WHERE UNIX_TIMESTAMP(NOW())-UNIX_TIMESTAMP( logendtime )<=30
查詢30秒內記錄的總數，loguser等於2的記錄的總數和，和 loguser等於3的記錄的總數.
if( logusertype =2, logusertype, 0 ) 如果logusetype等於2 就在logusertype上累加，否則加0。
sum( if( logusertype =2, logusertype, 0 ) ) 把logusertype都累加起來。
sum( if( logusertype =2, logusertype, 0 ) ) /2 AS a, 除以2是統計個數。
UNIX_TIMESTAMP(NOW())計算當前時間的秒數，
UNIX_TIMESTAMP( logendtime )計算logendtime的秒數
