若何經由過程SQL找出2個內外值分歧的列的辦法

若何經由過程SQL找出2個內外值分歧的列的辦法。本站提示廣大學習愛好者：（若何經由過程SQL找出2個內外值分歧的列的辦法）文章只能為提供參考，不一定能成為您想要的結果。以下是若何經由過程SQL找出2個內外值分歧的列的辦法正文

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以下有兩個表，他們的構造完整雷同，請經由過程SQL找出值分歧的列。

Student_1

NAME AGE SCORE peter 26 100 jack 25 96 daniel 26 48 bark 21 69

 

 

Student_2

NAME AGE SCORE peter 26 89 jack 25 96 daniel 26 48 bark 21 69

 

辦法一 -- NOT EXISTS：


SELECT *
FROM Student_1 S1
WHERE NOT EXISTS
  (SELECT *
  FROM Student_2 S2
  WHERE S1.name = S2.name
  AND S1.age    = S2.age
  AND S1.score  = S2.score
  )
UNION ALL
SELECT *
FROM STUDENT_2 S2
WHERE NOT EXISTS
  (SELECT *
  FROM STUDENT_1 S1
  WHERE S1.name = S2.name
  AND S1.age    = S2.age
  AND S1.score  = S2.score
  );

辦法二 -- MINUS

(SELECT * FROM Student_1
MINUS
SELECT * FROM Student_2)
UNION ALL
(SELECT * FROM Student_2
MINUS
SELECT * FROM Student_1)

辦法三 -- HAVING GROUP BY

SELECT DISTINCT name, age, score FROM (
SELECT * FROM Student_1
UNION ALL
SELECT * FROM Student_2
)GROUP BY name, age, score HAVING COUNT(*)=1 ;