MySQL 查詢成果取交集的完成辦法

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1
MySQL中若何完成以下SQL查詢
(SELECT S.Name
FROM STUDENT S, TRANSCRIPT T
WHERE S.StudId = T.StudId AND T.CrsCode = 'CS305')
INTERSECT
(SELECT S.Name
FROM STUDENT S, TRANSCRIPT T
WHERE S.StudId = T.StudId AND T.CrsCode = 'CS315')
請列位不惜賜教，小弟先謝過~
解：
取交集
select a.* from
(
SELECT S.Name
FROM STUDENT S, TRANSCRIPT T
WHERE S.StudId = T.StudId AND T.CrsCode = 'CS305'
) as a
cross join
(
SELECT S.Name
FROM STUDENT S, TRANSCRIPT T
WHERE S.StudId = T.StudId AND T.CrsCode = 'CS315'
) as b on a.Name = b.Name;

2.
SELECT * FROM (
SELECT DISTINCT col1 FROM t1 WHERE...
UNION ALL
SELECT DISTINCT col1 FROM t1 WHERE...
) AS tbl
GROUP BY tbl.col1 HAVING COUNT(*) = 2

3.
交集：
SELECT * FROM table1 AS a JOIN table2 AS b ON a.name =b.name
舉例：
表a:
FieldA
001
002
003
表b:
FieldA
001
002
003
004
就教若何能力得出以下成果集，即表A, B行交集
FieldA
001
002
003
謎底：select a.FieldA from a inner join b on a.FieldA=b.FieldA
差集：
NOT IN 表現差集
SELECT * FROM table1 WHERE name NOT IN (SELECT name FROM table2)