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/*-------------------------------- 求2個或以上字段為NULL 的記錄 t1: id, id1, id2, id3, id4, id5, id6 在t1 表中有個字段; 其中id是主鍵; 怎樣打印其中個字段或以上為NULL 的記錄id? 另外,存儲過程中怎麼實現按順序一條一條讀取記錄最方便? 注:主鍵id 是沒有順序的,也可能是字符串的; -----------------------------------------*/ drop table if exists t1; create table t1(id int,id1 int,id2 int,id3 int,id4 int,id5 int,id6 int); insert t1 select 1,1,1,1,1,null,null union all select 2,null,null,null,1,2,3 union all select 3,1,2,3,4,5,6 union all select 4,1,2,3,4,5,null union all select 5,null,3,4,null,null,null ; delimiter $$ create procedure usp_c_null() begin declare n_c int; declare idd int; declare cur cursor for select id,case char_length(concat(ifnull(id1,'@'),ifnull(id2,'@'),ifnull(id3,'@'),ifnull(id4,'@'),ifnull(id5,'@'),ifnull(id6,'@'))) -char_length(replace(concat(ifnull(id1,'@'),ifnull(id2,'@'),ifnull(id3,'@'),ifnull(id4,'@'),ifnull(id5,'@'),ifnull(id6,'@')),'@','') ) when 6 then 6 when 5 then 5 when 4 then 4 when 3 then 3 when 2 then 2 when 1 then 1 else 0 end as c from t1; declare exit HANDLER for not found close cur ; open cur; repeat fetch cur into idd,n_c; if(n_c>=2) then select * from t1 where id=idd; end if ; until 0 end repeat; close cur; end ; $$ delimiter ; /* +------+------+------+------+------+------+------+ | id | id1 | id2 | id3 | id4 | id5 | id6 | +------+------+------+------+------+------+------+ | 1 | 1 | 1 | 1 | 1 | NULL | NULL | +------+------+------+------+------+------+------+ 1 row in set (0.10 sec) +------+------+------+------+------+------+------+ | id | id1 | id2 | id3 | id4 | id5 | id6 | +------+------+------+------+------+------+------+ | 2 | NULL | NULL | NULL | 1 | 2 | 3 | +------+------+------+------+------+------+------+ 1 row in set (0.14 sec) +------+------+------+------+------+------+------+ | id | id1 | id2 | id3 | id4 | id5 | id6 | +------+------+------+------+------+------+------+ | 5 | NULL | 3 | 4 | NULL | NULL | NULL | +------+------+------+------+------+------+------+ 1 row in set (0.17 sec) */