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 程式師世界 >> 數據庫知識 >> Oracle數據庫 >> 關於Oracle數據庫 >> oracle sql select語句的使用方法

oracle sql select語句的使用方法

編輯:關於Oracle數據庫

       select格式:

      SELECT [ ALL | DISTINCT ] <字段表達式1[,<字段表達式2[,…]

      FROM <表名1>,<表名2>[,…]

      [WHERE <篩選擇條件表達式>]

      [GROUP BY <分組表達式> [HAVING<分組條件表達式>]]

      [ORDER BY <字段>[ASC | DESC]]

      語句說明:

      []方括號為可選項

      [GROUP BY <分組表達式> [HAVING<分組條件表達式>]]

      指將結果按<分組表達式>的值進行分組,該值相等的記錄為一組,帶【HAVING】

      短語則只有滿足指定條件的組才會輸出。

      [ORDER BY <字段>[ASC | DESC]]

      顯示結果要按<字段>值升序或降序進行排序

      練習:

      1:表hkb_test_sore取出成績sore前5名的記錄,

      2:取第5名的記錄

      1,答案select a.sore_id, a.sore

      from (select * from hkb_test_sore order by sore desc) a

      where rownum <=5

      2,答案select a.sore_id, a.sore

      from (select * from hkb_test_sore order by sore desc) a

      where rownum <=5

      minus

      select a.sore_id, a.sore

      from (select * from hkb_test_sore order by sore desc) a

      where rownum <=4;

      3:查詢兩個分數一樣的記錄

      select *

      from hkb_test_sore a

      where a.sore = (select sore

      from hkb_test_sore a

      group by a.sore

      having count(a.sore) = 2);

      union,union all,intersect,minus的區別:

      SQL> select * from hkb_test2;

      X Y

      ---- -----

      a 1

      b 2

      c 3

      g 4

      SQL> select * from hkb_test3;

      X Y

      ---- -----

      a 1

      b 2

      e 3

      f 4

      SQL> select * from hkb_test2;

      X Y

      ---- -----

      a 1

      b 2

      c 3

      g 4

      SQL> select * from hkb_test3;

      X Y

      ---- -----

      a 1

      b 2

      e 3

      f 4

      SQL> select * from hkb_test2

      2 union

      3 select * from hkb_test3;

      X Y

      ---- -----

      a 1

      b 2

      c 3

      e 3

      f 4

      g 4

      6 rows selected

      SQL> select * from hkb_test2

      2 union all

      3 select * from hkb_test3;

      X Y

      ---- -----

      a 1

      b 2

      c 3

      g 4

      a 1

      b 2

      e 3

      f 4

      8 rows selected

      SQL> select * from hkb_test2

      2 intersect

      3 select * from hkb_test3;

      X Y

      ---- -----

      a 1

      b 2

      SQL> select * from hkb_test2

      2 minus

      3 select * from hkb_test3;

      X Y

      ---- -----

      c 3

      g 4

      綜合上面實例看個完整的實例

      SQL>

      SQL>

      SQL> -- create demo table

      SQL> create table Employee(

      2 ID VARCHAR2(4 BYTE) NOT NULL primary key,

      3 First_Name VARCHAR2(10 BYTE),

      4 Last_Name VARCHAR2(10 BYTE),

      5 Start_Date DATE,

      6 End_Date DATE,

      7 Salary Number(8,2),

      8 City VARCHAR2(10 BYTE),

      9 Description VARCHAR2(15 BYTE)

      10 )

      11 /

      Table created.

      SQL>

      SQL> -- prepare data

      SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

      2 values ('01','Jason', 'Martin', to_date('19960725','YYYYMMDD'), to_date('20060725','YYYYMMDD'), 1234.56, 'Toronto', 'Programmer')

      3 /

      1 row created.

      SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

      2 values('02','Alison', 'Mathews', to_date('19760321','YYYYMMDD'), to_date('19860221','YYYYMMDD'), 6661.78, 'Vancouver','Tester')

      3 /

      1 row created.

      SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

      2 values('03','James', 'Smith', to_date('19781212','YYYYMMDD'), to_date('19900315','YYYYMMDD'), 6544.78, 'Vancouver','Tester')

      3 /

      1 row created.

      SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

      2 values('04','Celia', 'Rice', to_date('19821024','YYYYMMDD'), to_date('19990421','YYYYMMDD'), 2344.78, 'Vancouver','Manager')

      3 /

      1 row created.

      SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

      2 values('05','Robert', 'Black', to_date('19840115','YYYYMMDD'), to_date('19980808','YYYYMMDD'), 2334.78, 'Vancouver','Tester')

      3 /

      1 row created.

      SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

      2 values('06','Linda', 'Green', to_date('19870730','YYYYMMDD'), to_date('19960104','YYYYMMDD'), 4322.78,'New York', 'Tester')

      3 /

      1 row created.

      SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

      2 values('07','David', 'Larry', to_date('19901231','YYYYMMDD'), to_date('19980212','YYYYMMDD'), 7897.78,'New York', 'Manager')

      3 /

      1 row created.

      SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

      2 values('08','James', 'Cat', to_date('19960917','YYYYMMDD'), to_date('20020415','YYYYMMDD'), 1232.78,'Vancouver', 'Tester')

      3 /

      1 row created.

      SQL>

      SQL>

      SQL>

      SQL> -- display data in the table

      SQL> select * from Employee

      2 /

      ID FIRST_NAME LAST_NAME START_DAT END_DATE SALARY CITY DESCRIPTION

      ---- -------------------- -------------------- --------- --------- ---------- ---------- ---------------

      01 Jason Martin 25-JUL-96 25-JUL-06 1234.56 Toronto Programmer

      02 Alison Mathews 21-MAR-76 21-FEB-86 6661.78 Vancouver Tester

      03 James Smith 12-DEC-78 15-MAR-90 6544.78 Vancouver Tester

      04 Celia Rice 24-OCT-82 21-APR-99 2344.78 Vancouver Manager

      05 Robert Black 15-JAN-84 08-AUG-98 2334.78 Vancouver Tester

      06 Linda Green 30-JUL-87 04-JAN-96 4322.78 New York Tester

      07 David Larry 31-DEC-90 12-FEB-98 7897.78 New York Manager

      08 James Cat 17-SEP-96 15-APR-02 1232.78 Vancouver Tester

      8 rows selected.

      SQL>

      SQL>

      SQL> SELECT id, first_name, last_name FROM employee

      2 /

      ID FIRST_NAME LAST_NAME

      ---- -------------------- --------------------

      01 Jason Martin

      02 Alison Mathews

      03 James Smith

      04 Celia Rice

      05 Robert Black

      06 Linda Green

      07 David Larry

      08 James Cat

      8 rows selected.

      在ORACLE中實現SELECT TOP N的方法

      1.在ORACLE中實現SELECT TOP N

      由於ORACLE不支持SELECT TOP語句,所以在ORACLE中經常是用ORDER BY跟ROWNUM的組合來實現SELECT TOP N的查詢。

      簡單地說,實現方法如下所示:

      SELECT 列名1...列名n FROM

      (SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

      WHERE ROWNUM <= N(抽出記錄數)

      ORDER BY ROWNUM ASC

      下面舉個例子簡單說明一下。

      顧客表customer(id,name)有如下數據:

      ID NAME

      01 first

      02 Second

      03 third

      04 forth

      05 fifth

      06 sixth

      07 seventh

      08 eighth

      09 ninth

      10 tenth

      11 last

      則按NAME的字母順抽出前三個顧客的SQL語句如下所示:

      SELECT * FROM

      (SELECT * FROM CUSTOMER ORDER BY NAME)

      WHERE ROWNUM <= 3

      ORDER BY ROWNUM ASC

      輸出結果為:

      ID NAME

      08 eighth

      05 fifth

      01 first

      2.在TOP N紀錄中抽出第M(M <= N)條記錄

      在得到了TOP N的數據之後,為了抽出這N條記錄中的第M條記錄,我們可以考慮從ROWNUM著手。我們知道,ROWNUM是記錄表中數據編號的一個隱藏子段,所以可以在得到TOP N條記錄的時候同時抽出記錄的ROWNUM,然後再從這N條記錄中抽取記錄編號為M的記錄,即使我們希望得到的結果。

      從上面的分析可以很容易得到下面的SQL語句。

      SELECT 列名1...列名n FROM

      (

      SELECT ROWNUM RECNO, 列名1...列名nFROM

      (SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

      WHERE ROWNUM <= N(抽出記錄數)

      ORDER BY ROWNUM ASC

      )

      WHERE RECNO = M(M <= N)

      同樣以上表的數據為基礎,那麼得到以NAME的字母順排序的第二個顧客的信息的SQL語句應該這樣寫:

      SELECT ID, NAME FROM

      (

      SELECT ROWNUM RECNO, ID, NAME FROM

      (SELECT * FROM CUSTOMER ORDER BY NAME)

      WHERE ROWNUM <= 3

      ORDER BY ROWNUM ASC )

      WHERE RECNO = 2

      結果則為:

      ID NAME

      05 fifth

      3.抽出按某種方式排序的記錄集中的第N條記錄

      在2的說明中,當M = N的時候,即為我們的標題講的結果。實際上,2的做法在裡面N>M的部分的數據是基本上不會用到的,我們僅僅是為了說明方便而采用。

      如上所述,則SQL語句應為:

      SELECT 列名1...列名n FROM

      (

      SELECT ROWNUM RECNO, 列名1...列名nFROM

      (SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

      WHERE ROWNUM <= N(抽出記錄數)

      ORDER BY ROWNUM ASC

      )

      WHERE RECNO = N

      那麼,2中的例子的SQL語句則為:

      SELECT ID, NAME FROM

      (

      SELECT ROWNUM RECNO, ID, NAME FROM

      (SELECT * FROM CUSTOMER ORDER BY NAME)

      WHERE ROWNUM <= 2

      ORDER BY ROWNUM ASC

      )

      WHERE RECNO = 2

      結果為:

      ID NAME

      05 fifth

      4.抽出按某種方式排序的記錄集中的第M條記錄開始的X條記錄

      3裡所講得僅僅是抽取一條記錄的情況,當我們需要抽取多條記錄的時候,此時在2中的N的取值應該是在N >= (M + X - 1)這個范圍內,當讓最經濟的取值就是取等好的時候了的時候了。當然最後的抽取條件也不是RECNO = N了,應該是RECNO BETWEEN M AND (M + X - 1)了,所以隨之而來的SQL語句則為:

      SELECT 列名1...列名n FROM

      (

      SELECT ROWNUM RECNO, 列名1...列名nFROM

      (

      SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

      WHERE ROWNUM <= N (N >= (M + X - 1))

      ORDER BY ROWNUM ASC

      )

      WHERE RECNO BETWEEN M AND (M + X - 1)

      同樣以上面的數據為例,則抽取NAME的字母順的第2條記錄開始的3條記錄的SQL語句為:

      SELECT ID, NAME FROM

      (

      SELECT ROWNUM RECNO, ID, NAME FROM

      (SELECT * FROM CUSTOMER ORDER BY NAME)

      WHERE ROWNUM <= (2 + 3 - 1)

      ORDER BY ROWNUM ASC

      )

      WHERE RECNO BETWEEN 2 AND (2 + 3 - 1)

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