1. 做一個3*3的加法表
SQL> select a||'+'||b||'='||(a+b) from (select rownum a from all_objects where rownum<4), (select rownum b from all_objects where rownum<4); A||'+'||B||'='||(A+B) ------------------------------------------------------------------------------------------------------------------------ 1+1=2 1+2=3 1+3=4 2+1=3 2+2=4 2+3=5 3+1=4 3+2=5 3+3=6 9 rows selected.
2. 做一個5*5的乘法表
with multiplier as (select rownum n from dual connect by rownum<6) select a.n||'*'||b.n||'='||(a.n*b.n) from multiplier a, multiplier b
3. 不用connect by,只用dual表,構造出1到128
with a as (select 1 from dual union all select 1 from dual) select rownum from a,a,a,a,a,a,a
4. 池塘邊上有牛和鵝若干,小華總共看到15個頭42條腿,請問牛和鵝各有多少?
with a as (select 1 from dual union all select 1 from dual), b as (select rownum n from a,a,a,a) select x.n num_of_bull, y.n num_of_goose from b x, b y where x.n*4+y.n*2=42 and x.n+y.n=15
5. 百錢買雞兔:老母雞3塊1只,小母雞4塊5只,大白兔2塊1只,小白兔3塊4只,要求買回來的動物總共100只,並且腳不少於240條不多於320條。花100塊錢來買這些動物,要求每種動物都至少要購買一只且錢正好花完,輸出所有的可能情況。
with t as (select 1 from dual union all select 1 from dual), t1 as (select rownum n from t,t,t,t,t) select a.n lmj,5*b.n xmj,c.n dbt,4*d.n xbt from t1 a,t1 b,t1 c,t1 d where 3*a.n+b.n*4+c.n*2+d.n*3=100 and a.n+5*b.n+c.n+4*d.n=100 and (2*a.n+10*b.n+4*c.n+16*d.n between 240 and 320) and a.n<>0 and b.n<>0 and c.n<>0 and d.n<>0;
6. 每個雇員的薪水(SAL)都對應到一個薪水級別(SALGRADE表中的GRADE字段),哪個薪水級別上的雇員數量最多?輸出該薪水級別信息。本題需要用三種不同的寫法作答。
第一種寫法:
select * from salgrade where grade=(select grade from (select s.grade,count(*) from emp e,salgrade s where e.sal between s.losal and s.hisal group by s.grade order by 2 desc) where rownum=1);
第二種寫法:
with t as (select s.grade,count(*) num from emp e,salgrade s where e.sal between s.losal and s.hisal group by s.grade), t1 as (select max(num) maxnum from t) select s.* from salgrade s,t,t1 where s.grade=t.grade and t.num=t1.maxnum;
第三種寫法:
select * from salgrade where exists (select 1 from (select grade from (select s.grade,count(*) from emp e,salgrade s where e.sal between s.losal and s.hisal group by s.grade order by 2 desc) where rownum=1) s where s.grade=salgrade.grade);