Oracle中檢查外鍵是否有索引的SQL腳本分享，oraclesql

Oracle中檢查外鍵是否有索引的SQL腳本分享，oraclesql

復制代碼 代碼如下:
COLUMN COLUMNS format a30 word_wrapped
COLUMN tablename format a15 word_wrapped
COLUMN constraint_name format a15 word_wrapped
SELECT TABLE_NAME,
       CONSTRAINT_NAME,
       CNAME1 || NVL2(CNAME2, ',' || CNAME2, NULL) ||
       NVL2(CNAME3, ',' || CNAME3, NULL) ||
       NVL2(CNAME4, ',' || CNAME4, NULL) ||
       NVL2(CNAME5, ',' || CNAME5, NULL) ||
       NVL2(CNAME6, ',' || CNAME6, NULL) ||
       NVL2(CNAME7, ',' || CNAME7, NULL) ||
       NVL2(CNAME8, ',' || CNAME8, NULL) COLUMNS
  FROM (SELECT B.TABLE_NAME,
               B.CONSTRAINT_NAME,
               MAX(DECODE(POSITION, 1, COLUMN_NAME, NULL)) CNAME1,
               MAX(DECODE(POSITION, 2, COLUMN_NAME, NULL)) CNAME2,
               MAX(DECODE(POSITION, 3, COLUMN_NAME, NULL)) CNAME3,
               MAX(DECODE(POSITION, 4, COLUMN_NAME, NULL)) CNAME4,
               MAX(DECODE(POSITION, 5, COLUMN_NAME, NULL)) CNAME5,
               MAX(DECODE(POSITION, 6, COLUMN_NAME, NULL)) CNAME6,
               MAX(DECODE(POSITION, 7, COLUMN_NAME, NULL)) CNAME7,
               MAX(DECODE(POSITION, 8, COLUMN_NAME, NULL)) CNAME8,
               COUNT(*) COL_CNT
          FROM (SELECT SUBSTR(TABLE_NAME, 1, 30) TABLE_NAME,
                       SUBSTR(CONSTRAINT_NAME, 1, 30) CONSTRAINT_NAME,
                       SUBSTR(COLUMN_NAME, 1, 30) COLUMN_NAME,
                       POSITION
                  FROM USER_CONS_COLUMNS) A,
               USER_CONSTRAINTS B
         WHERE A.CONSTRAINT_NAME = B.CONSTRAINT_NAME
           AND B.CONSTRAINT_TYPE = 'R'
         GROUP BY B.TABLE_NAME, B.CONSTRAINT_NAME) CONS
 WHERE COL_CNT > ALL
 (SELECT COUNT(*)
          FROM USER_IND_COLUMNS I
         WHERE I.TABLE_NAME = CONS.TABLE_NAME
           AND I.COLUMN_NAME IN (CNAME1, CNAME2, CNAME3, CNAME4, CNAME5,
                CNAME6, CNAME7, CNAME8)
           AND I.COLUMN_POSITION <= CONS.COL_CNT
         GROUP BY I.INDEX_NAME)
/

在上面的基礎上修改了一下，可以檢查所有的用戶。
復制代碼 代碼如下:
SET linesize 400;
COLUMN OWNER format a10 word_wrapped
COLUMN COLUMNS format a30 word_wrapped
COLUMN TABLE_NAME format a15 word_wrapped
COLUMN CONSTRAINT_NAME format a40 word_wrapped
SELECT OWNER,
     TABLE_NAME,
       CONSTRAINT_NAME,
       CNAME1 || NVL2(CNAME2, ',' || CNAME2, NULL) ||
       NVL2(CNAME3, ',' || CNAME3, NULL) ||
       NVL2(CNAME4, ',' || CNAME4, NULL) ||
       NVL2(CNAME5, ',' || CNAME5, NULL) ||
       NVL2(CNAME6, ',' || CNAME6, NULL) ||
       NVL2(CNAME7, ',' || CNAME7, NULL) ||
       NVL2(CNAME8, ',' || CNAME8, NULL) COLUMNS
  FROM (SELECT B.OWNER,B.TABLE_NAME,
               B.CONSTRAINT_NAME,
               MAX(DECODE(POSITION, 1, COLUMN_NAME, NULL)) CNAME1,
               MAX(DECODE(POSITION, 2, COLUMN_NAME, NULL)) CNAME2,
               MAX(DECODE(POSITION, 3, COLUMN_NAME, NULL)) CNAME3,
               MAX(DECODE(POSITION, 4, COLUMN_NAME, NULL)) CNAME4,
               MAX(DECODE(POSITION, 5, COLUMN_NAME, NULL)) CNAME5,
               MAX(DECODE(POSITION, 6, COLUMN_NAME, NULL)) CNAME6,
               MAX(DECODE(POSITION, 7, COLUMN_NAME, NULL)) CNAME7,
               MAX(DECODE(POSITION, 8, COLUMN_NAME, NULL)) CNAME8,
               COUNT(*) COL_CNT
          FROM (SELECT SUBSTR(TABLE_NAME, 1, 30) TABLE_NAME,
                       SUBSTR(CONSTRAINT_NAME, 1, 30) CONSTRAINT_NAME,
                       SUBSTR(COLUMN_NAME, 1, 30) COLUMN_NAME,
                       POSITION
                  FROM DBA_CONS_COLUMNS WHERE OWNER NOT IN ('SYS','SYSTEM','SYSMAN','HR','OE','EXFSYS','DBSNMP','MDSYS','OLAPSYS','SCOTT','EXFSYS','SH','PM','CTXSYS')) A,
               DBA_CONSTRAINTS B
         WHERE A.CONSTRAINT_NAME = B.CONSTRAINT_NAME
           AND B.CONSTRAINT_TYPE = 'R'
         GROUP BY B.OWNER,B.TABLE_NAME, B.CONSTRAINT_NAME) CONS
 WHERE COL_CNT > ALL
 (SELECT COUNT(*)
          FROM DBA_IND_COLUMNS I
         WHERE I.TABLE_NAME = CONS.TABLE_NAME AND I.TABLE_OWNER=CONS.OWNER
           AND I.COLUMN_NAME IN (CNAME1, CNAME2, CNAME3, CNAME4, CNAME5,
                CNAME6, CNAME7, CNAME8)
           AND I.COLUMN_POSITION <= CONS.COL_CNT
         GROUP BY I.INDEX_NAME)
/

在Oracle中，有沒有查看一個表外鍵的SQL語句？

已驗證:
select INDEX_NAME 索引名, b.TABLE_NAME 主鍵表名, a.TABLE_NAME 外鍵表名, CONSTRAINT_TYPE, CONSTRAINT_NAME 約束名
from all_indexes a, all_constraints b
where b.TABLE_NAME='AC' AND CONSTRAINT_TYPE IN('P','R')
and R_CONSTRAINT_NAME=INDEX_NAME(+)
/
CONSTRAINT_TYPE='P'為主鍵,='R'為外鍵
 

ORACLE 11g，怎查詢所有外鍵沒有索引？

查詢當前用戶的

column con format a20 word_wrapped
column idx format a20 word_wrapped
column table_name format a30 word_wrapped

select decode( b.table_name, NULL, '****', 'ok' ) Status,
a.table_name, a.columns con, b.columns idx
from
( select substr(a.table_name,1,30) table_name,
substr(a.constraint_name,1,30) constraint_name,
max(decode(position, 1, substr(column_name,1,30),NULL)) ||
max(decode(position, 2,', '||substr(column_name,1,30),NULL)) ||
max(decode(position, 3,', '||substr(column_name,1,30),NULL)) ||
max(decode(position, 4,', '||substr(column_name,1,30),NULL)) ||
max(decode(position, 5,', '||substr(column_name,1,30),NULL)) ||
max(decode(position, 6,', '||substr(column_name,1,30),NULL)) ||
max(decode(position, 7,', '||substr(column_name,1,30),NULL)) ||
max(decode(position, 8,', '||substr(column_name,1,30),NULL)) ||
max(decode(position, 9,', '||substr(column_name,1,30),NULL)) ||
max(decode(position,10,', '||substr(column_name,1,30),NULL)) ||
max(decode(position,11,', '||substr(column_name,1,30),NULL)) ||
max(decode(position,12,', '||substr(column_name,1,30),NULL)) ||
max(decode(position,13,', '||substr(column_name,1,30),NULL)) ||
max(decode(position,14,', '||substr......余下全文>>