獲得MSSQL 表構造中字段的備注、主鍵等信息的sql。本站提示廣大學習愛好者：（獲得MSSQL 表構造中字段的備注、主鍵等信息的sql）文章只能為提供參考，不一定能成為您想要的結果。以下是獲得MSSQL 表構造中字段的備注、主鍵等信息的sql正文
1、MSSQL2000
SELECT
表名 = case when a.colorder=1 then d.name else '' end,
表解釋 = case when a.colorder=1 then isnull(f.value,'') else '' end,
字段序號 = a.colorder,
字段名 = a.name,
標識 = case when COLUMNPROPERTY( a.id,a.name,'IsIdentity')=1 then '√'else '' end,
主鍵 = case when exists(SELECT 1 FROM sysobjects where xtype='PK' and parent_obj=a.id and name in (
SELECT name FROM sysindexes WHERE indid in(
SELECT indid FROM sysindexkeys WHERE id = a.id AND colid=a.colid))) then '√' else '' end,
類型 = b.name,
占用字節數 = a.length,
長度 = COLUMNPROPERTY(a.id,a.name,'PRECISION'),
小數位數 = isnull(COLUMNPROPERTY(a.id,a.name,'Scale'),0),
許可空 = case when a.isnullable=1 then '√'else '' end,
默許值 = isnull(e.text,''),
字段解釋 = isnull(g.[value],'')
FROM
syscolumns a
left join
systypes b
on
a.xusertype=b.xusertype
inner join
sysobjects d
on
a.id=d.id and d.xtype='U' and d.name<>'dtproperties'
left join
syscomments e
on
a.cdefault=e.id
left join
sysproperties g
on
a.id=g.id and a.colid=g.smallid
left join
sysproperties f
on
d.id=f.id and f.smallid=0
where
d.name='FI_dept' --假如只查詢指定表,加上此前提
order by
a.id,a.colorder
2、MSSQL2005
use test--數據庫
go
--2005完成字段屬性統計(2000裡的體系表sysproperties描寫表、字段不存在，2005裡用sys.extended_properties視圖替換)
select
[表名]=c.Name,
[表解釋]=isnull(f.[value],''),
[列名]=a.Name,
[列序號]=a.Column_id,
[標識]=case when is_identity=1 then '√' else '' end,
[主鍵]=case when exists(select 1 from sys.objects where parent_object_id=a.object_id and type=N'PK' and name in
(select Name from sys.indexes where index_id in
(select indid from sysindexkeys where and colid=a.column_id)))
then '√' else '' end,
[類型]=b.Name,
[字節數]=case when a.[max_length]=-1 and b.Name!='xml' then 'max/2G'
when b.Name='xml' then ' 2^31-1字節/2G'
else rtrim(a.[max_length]) end,
[長度]=ColumnProperty(a.object_id,a.Name,'Precision'),
[小數]=isnull(ColumnProperty(a.object_id,a.Name,'Scale'),0),
[能否為空]=case when a.is_nullable=1 then '√' else '' end,
[列解釋]=isnull(e.[value],''),
[默許值]=isnull(d.text,'')
from
sys.columns a
left join
sys.types b on a.user_type_id=b.user_type_id
inner join
sys.objects c on a.object_id=c.object_id and c.Type='U'
left join
syscomments d on a.default_object_id=d.ID
left join
sys.extended_properties e on e.major_id=c.object_id and e.minor_id=a.Column_id and e.class=1
left join
sys.extended_properties f on f.major_id=c.object_id and f.minor_id=0 and f.class=1
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成果：
