create function Get_StrArrayLength
(
@str varchar(5000), --要分割的字符串
@split varchar(10) --分隔符號
)
returns int
as
begin
declare @location int
declare @start int
declare @length int
set @str=ltrim(rtrim(@str))
set @location=charindex(@split,@str)
set @length=1
while @location<>0
begin
set @start=@location+1
set @location=charindex(@split,@str,@start)
set @length=@length+1
end
return @length
end
調用示例:select dbo.Get_StrArrayLength('1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48',',')
返回值:4
二、按指定符號分割字符串,返回分割後指定索引的第幾個元素,象數組一樣方便
--alter function Get_StrArrayStrOfIndex
create function Get_StrArrayStrOfIndex
(
@str varchar(5000), --要分割的字符串
@split varchar(10), --分隔符號
@index int --取第幾個元素
)
returns varchar(5000)
as
begin
declare @location int
declare @start int
declare @next int
declare @seed int
set @str=ltrim(rtrim(@str))
set @start=1
set @next=1
set @seed=len(@split)
set @location=charindex(@split,@str)
while @location<>0 and @index>@next
begin
set @start=@location+@seed
set @location=charindex(@split,@str,@start)
set @next=@next+1
end
if @location =0 select @location =len(@str)+1
--這兒存在兩種情況:1、字符串不存在分隔符號 2、字符串中存在分隔符號,跳出while循環後,@location為0,那默認為字符串後邊有一個分隔符號。
return substring(@str,@start,@location-@start)
end